Answer:
1. d. 84g
2. c. 77.4%
Explanation:
1. Based on the reaction 2 moles of Na produce 2 moles of NaCl.
The moles of Na (22.99g/mol) in 33g are:
33g * (1mol / 22.99g) = 1.435 moles Na = 1.435 moles NaCl must be produced.
The mass of NaCl is (Molar mass: 58.44g/mol):
1.435moles * (58.44g / mol) = 84g
d. 84g
2. Percent yield is defined as 100 times the ratio between actual yield (65g) and theoretical yield (84g). The percent yield is:
65g / 84g * 100 =
c. 77.4%
We say that the solution is unsaturated.
Explanation:
If the salt solubility is 36 g in 0.1 L of water then we can dissolve 360 g of salt in 1 L of water.
Because the solution contains 200 g of salt in 1 L of water, the solution is unsaturated because more salt can be added until we reach the saturation point.
We call the solution dilute when we compare the concentration of a solution with the concentration of another solution, but here we do not compare different solutions.
Learn more about:
solubility
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Answer:
Polarity in chemistry referred to physical properties of compounds related to solubility, melting and boiling properties.
Polarity of black pepper can be seen when black pepper is sprinkled on water. The balck pepper float on water and get displaced if touched.
It means black pepper is non-polar and have no difference in electronegativity between bonded atoms. Black pepper is so light in weight and non-polar, the surface tension of water keep it floating in the water.
The correct option is C.
The pitch of a string refers to the quality of sound that is produced by the string when it vibrates. There are three basic factors that affect the quality of pitch of a string, these are: the tension, the thickness of the string and the length of the string. The higher the thickness of the string, the lower the pitch of the string, thus, increasing the thickness of the string will lower the pitch.
Answer: 429 grams of
should be added to 1.3 L of water to prepare 2.0 M solution
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

where,
n = moles of solute
=
= volume of solution in Liters
Now put all the given values in the formula of molarity, we get


Therefore, 429 grams of
should be added to 1.3 L of water to prepare 2.0 M solution