<span>Molar mass of chloroform (CHCl3)
C = 1 * 12 = 12 a.m.u
H = 1 * 1 = 1 a.m.u
Cl = 3 * 35.5 = 106.5 a.m.u
Molar Mass (CHCl3) = 12 + 1 + 106.5 = 119.5 g / mol
Knowing that:
The value of Avogadro's constant corresponds to approximately </span>

molecules, if chloroform contains

molecules. <span>
We have:
</span>

<span>
Now, how many grams are there in the chloroform molecule?
grams -------- molecules</span><span>
119,5 </span>→

x →




Answer:
Are u a boy or a girl so we can form a study group and the answer is C
Answer:
First part: The new volume of the gas is 1786 Liters.
Second part: The temperature required to change the volume of the gas sample is 347 °C
Explanation:
We assume the Charles - Gay Lussac law where, in constant pressure, volume of a gas changes directly proportional to Temperature (in Kelvin)
V1 / T1 = V2/T2
37°C + 273 = 310 K
82°C + 273 = 355 K
1560L / 310°K = V2 / 355K
(1560 / 310) . 355 = V2
1786 L = V2
1560 L / 310 K = 3120 L / T2
T2 = 3120 L . (310 K / 1560 L)
T2 = 620 K
620K - 273 = 347°C
I am not the best at this, but im pretty sure its below cloud
A.
H₃C-CH₃
this is called ethane
B.
H₃C-CH₂-CH₂-CH₃
this is called butane
C.H₃C-CH₂-CH₂-CH₂-CH₂-CH₃
this is called hexane
D.
H₃C-CH₂-CH₂-CH₂-CH₂-CH₂-CH₃
this is called heptane