Hey can you please help me posted picture of question

What is the wrong way to remember where you caught a lot of fish?

crimeas [40]

The wrongest way is to mark an ' X ' on the side of the boat.

6 0

3 years ago

Line L is perpendicular to a line with slope -5 and passes through (2, -2). Find an equation of line L and write the answer in t

irina [24]

Answer:

y=1x +8

5

Step-by-step explanation:

y-y1 = m(x-x1)

y+2 = -5(x-2)

y+2 = -5x + 10

y = -5x +8

Now to find line L we have to change the slope because it is perpendicular

y= 1x +8 (The slope is one fifth, but idk

5. to put it, I'm sorry)

4 0

3 years ago

If $4200 is invested into a savings account for which interest is compounded semiannually, and if the $4200 turns into $4900 in

serg [7]

x = interest rate

solve for x

4900 = 4200(1+x/2)^8

x = 0.0389 = 3.89%

6 0

3 years ago

Read 2 more answers

The currency in Sweden is the kroner. The exchange rate is approximately $1 for 7 Kroner. At this rate how many kroner would you

solmaris [256]

14 kroner because 7×2 is 14 and the 2 if from the $2

3 0

3 years ago

Read 2 more answers

A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a

UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

$P_{t}=P_{0}+500t$

Where $P_{t}$ = Population after t years

$P_{0}$ = Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = $\frac{5000}{500}$

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = $\frac{15000}{500}$

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = $\frac{35000}{500}$

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

$T_{n}=T_{0}(1+\frac{r}{100})^{t}$

$T_{n}$ = Population after t years

$T_{0}$ = Initial population

t = time in years

For double once,

Population after t years = 10000

$10000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{10000}{5000}$

$(1.05)^{t}=2$

Take log on both the sides

$log(1.05)^{t}=log2$

tlog(1.05) = log2

t = $\frac{log2}{log1.05}$

t = 14.20 years

For double twice,

Population after t years = 20000

$20000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{20000}{5000}$

$(1.05)^{t}=4$

Take log on both the sides

$log(1.05)^{t}=log4$

tlog(1.05) = log4

t = $\frac{log4}{log1.05}$

t = 28.413 years

For double thrice

Population after t years = 40000

$40000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{40000}{5000}$

$(1.05)^{t}=8$

Take log on both the sides

$log(1.05)^{t}=log8$

tlog(1.05) = log8

t = $\frac{log8}{log1.05}$

t = 42.620 years

4 0

3 years ago