All categories

3 years ago

Hey can you please help me posted picture of question

Mathematics

1 answer:

lisov135 [29]3 years ago

8 0

The correct answer would be C.439:))))))

You might be interested in

Solve for W -3W +27 = 6

vfiekz [6]

Answer:

the answer will be 7 w = 7

Step-by-step explanation:

5 0

3 years ago

Which of the following numbers is irrational

max2010maxim [7]

The square root of 5

6 0

3 years ago

Read 2 more answers

You paint of a wall in hour. At that rate, how long will it take you to paint one wall?

zysi [14]

Answer:

an hour....

Step-by-step explanation:

6 0

3 years ago

Use the quadratic formula to solve the following equation -3x^2-x-3=0

tigry1 [53]

Answer:

$x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i$ are two roots of equation $-3 x^{2}-x-3=0$

Solution:

Need to solve given equation using quadratic formula.

$-3 x^{2}-x-3=0$

General form of quadratic equation is $a x^{2}+b x+c=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}$

Since $b^{2}-4 a c$ is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

$\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}$

8 0

3 years ago

Can someone please help me with this?

GrogVix [38]

The circumference of a circle with radius $r$ is $2\pi r$ . If the length of the radius is tripled, then the circumference becomes $2\pi(3r)=3\cdot2\pi r$ , which is just 3 times the original circle's circumference.

4 0

3 years ago