how much work does an elephant do while moving a circus wagon 23 meters with a pulling force of 250N at an angle of 38 degrees?

Physics

1 answer:

Yuki888 [10]3 years ago

4 0

Answer:

The work done on the wagon is, W = 4531 J

Explanation:

Given data,

The displacement of the circus wagon, S = 23 m

The elephant pulled with a force, Fₐ = 250 N

The angle of direction of force with the horizontal, Ф = 38°

Therefore, the force in the horizontal direction is,

F = Fₐ Cos Ф

The work done on the wagon is

W = F · S

= Fₐ Cos Ф · S

= Fₐ · S · Cos Ф

= 250 · 23 · Cos 38°

= 4531 J

Hence, the work done on the wagon is, W = 4531 J

You might be interested in

How can you increase the momentum of an object

77julia77 [94]

The answer is <span>B. by increasing its mass. Hope it help!</span>

6 0

3 years ago

Read 2 more answers

The wattage marked on a lightbulb is not an inherent property of the bulb but depends on the voltage to which it is connected, u

Mashutka [201]

Answer:

The current that flows through the lamp is 0.5 A.

Explanation:

A lamp functions like a resistor and the real power absorbed by a resistor is given by the product of the voltage drop across it's terminals and the current that flows through it. If we wish to find the current that this lamp draws we should divide the wattage given (60 W) by the voltage drop provided (120 V). We then have:

i = P/V = 60/120 = 0.5 A.

5 0

3 years ago

Through what media does mechanical waves move

Aleks [24]

A mechanical wave moves through all matter

6 0

3 years ago

What is the three laws of electrostatics?

dangina [55]

The force exerted between 2 point charges is directly proportional to the product of their strengths, is inversely proportional to the square of the distance between them and is inversely proportional to the absolute permittivity of the surrounding mediums.

I hope that helps somewhat, I'm only kind of sure that could be correct

5 0

3 years ago

Read 2 more answers

(a) Calculate the number of free electrons per cubic meter for gold assuming that there are 1.5 free electrons per gold atom. Th

KonstantinChe [14]

Answer:

Part A:

$n=8.85*10^{28}m^{-3}$