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2 years ago

Deduce the diamension of work

Physics

2 answers:

djyliett [7]2 years ago

7 0

Answer:

Explanation:Quantity

Dimension

Unit

SI Symbol

Formula

Base units:

length

[L]

meter

mass

[M]

kilogram

temperature

[Q]

kelvin

time

[T]

second

Derived units:

area

[L2]

square meter

volume

[L3]

cubic meter

velocity

[L T-1]

meter per second

m s-1

acceleration

[L T-2]

meter per second squared

m s-2

density

[M L-3]

kilogram per cubic meter

kg m-3

force

[M L T-2]

newton

kg m s-2

pressure

[M L-1 T-2]

pascal

N m-2

stress

[M L-1 T-2]

pascal

N m-2

energy

[M L2 T-2]

joule

N·m

quantity of heat

[M L2 T-2]

joule

N·m

work

[M L2 T-2]

joule

N·m

power

[M L2 T-3]

watt

J s-1

viscosity, dynamic

[M L-1 T-1]

pascal-second

Pa·s

viscosity, kinematic

[L2 T-1]

square meter per second

m2 s-1

specific heat

[L2 Q-1 T-2]

joule per kilogram-kelvin

J kg-1 K-

Mademuasel [1]2 years ago

4 0

Answer:

Unit of work done is Joule. Therefore, the dimension formula of work is represented as [M1 L2 T-2].Explanation:

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The unit for energy is the

nikitadnepr [17]

Explanation:

Joule (J) is the MKS unit of energy, equal to the force of one Newton acting through one meter.

4 0

3 years ago

You have designed a machine that requires 1000 J of work from a motor for every 800 J of useful work done by the machine. What i

valentinak56 [21]

Answer:

80%

Explanation:

$efficiency = \frac{useful \: work \: done}{total \: energy \: input}$

800 / 1000 = 0.8

Efficiency = 0.8 *100 = 80%

4 0

1 year ago

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton

pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:

$F = K * \Delta{x}$

$2\:N = 4\:N/cm*\Delta{x}$

$4\:N/cm*\Delta{x} = 2\:N$

$\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}$

simplify by 2

$\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}$

$\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark$

Answer:

B.) 1/2 cm

_______________________

I Hope this helps, greetings ... Dexteright02! =)

7 0

2 years ago

1) A person riding their bike on a nice cloudy day travels 50 meters in 20 seconds.

Rasek [7]

Answer:

5.59

Explanation:

50 meters in 10 seconds is 11.18, which is an easy way to remember. Just divided by 2

5 0

2 years ago

Water inside a tub rises from 15 mL to 19 mL when an object is submerged. If the mass of the object is 249, what's the density o

Alex_Xolod [135]

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 249 g

volume = final volume of water - initial volume of water

volume = 19 - 15 = 4 mL

We have

$density = \frac{249}{4} \\$

We have the final answer as

Hope this helps you

6 0

3 years ago

Deduce the diamension of work​

Deduce the diamension of work