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klemol [59]
3 years ago
5

Deduce the diamension of work​

Physics
2 answers:
djyliett [7]3 years ago
7 0

Answer:

Explanation:Quantity  

Dimension

Unit  

SI Symbol

Formula

Base units:    

length  

[L]

meter  

m

mass  

[M]

kilogram  

kg

temperature  

[Q]

kelvin  

K

time  

[T]

second  

s

Derived units:    

area  

[L2]

square meter  

m2

volume  

[L3]

cubic meter  

m3

velocity  

[L T-1]

meter per second  

m s-1

acceleration  

[L T-2]

meter per second squared  

m s-2

density  

[M L-3]

kilogram per cubic meter  

kg m-3

force  

[M L T-2]

newton  

N

kg m s-2

pressure  

[M L-1 T-2]

pascal  

Pa

N m-2

stress  

[M L-1 T-2]

pascal  

Pa

N m-2

energy  

[M L2 T-2]

joule  

J

N·m

quantity of heat  

[M L2 T-2]

joule  

J

N·m

work  

[M L2 T-2]

joule  

J

N·m

power  

[M L2 T-3]

watt  

W

J s-1

viscosity, dynamic  

[M L-1 T-1]

pascal-second  

Pa·s

viscosity, kinematic  

[L2 T-1]

square meter per second  

m2 s-1

specific heat  

[L2 Q-1 T-2]

joule per kilogram-kelvin  

J kg-1 K-

Mademuasel [1]3 years ago
4 0

Answer:

Unit of work done is Joule. Therefore, the dimension formula of work is represented as [M1 L2 T-2].Explanation:

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A boy is listening to the radio. The loudspeaker plays a musical note by vibrating 256 rimes esch second. How many times does th
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Answer:

 f_tympanum = 256 Hz.

Explanation:

The eardrum is the vibrating membrane of the human ear, it works by resonance, that is, an external stimulus (force) makes it vibrate, as the eardrum is extremely light it can vibrate at the same frequency of the incident sound.

Consequently if the incident vibration is f = 256 hz, the eardrum resonates at the same frequency

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As a reference the response of the eardrum goes from f = 20 Hz f = 20000 Hz

6 0
4 years ago
A machine does 1200 J of work in 1 min. What is the power developed
densk [106]

Answer:

20 watts

Explanation:

Big brain mode activated:

Power=1200J/60sec

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8 0
3 years ago
At the top of a pole vault, an athlete actually can do work pushing on the pole before releasing it. Suppose the pushing force t
Salsk061 [2.6K]

Answer:

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Explanation:

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\displaystyle{\int_{x_i}^{x_j}F(x)dx}

and substituting with the function of our problem:

\displaystyle{\int_{0}^{0.19}(140x-190x^2)dx\approx2.09\mathrm{J}}

5 0
4 years ago
An object experiences an acceleration of 6.8m/s2.As a result,it accelerates from rest to 24m/s.How much distance did it travel d
Hitman42 [59]

The distance covered by the object is 42.4 m

Explanation:

The motion of the object is a uniformly accelerated motion (at constant acceleration), therefore we can use the following suvat equation:

v^2 -u^2 = 2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the object in this problem, we have:

u = 0 (it starts from rest)

v = 24 m/s (final velocity)

a=6.8 m/s^2

Solving for s, we find the distance travelled by the object:

s=\frac{v^2-u^2}{2a}=\frac{24^2-0}{2(6.8)}=42.4 m

Learn more about accelerated motion:

brainly.com/question/9527152

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#LearnwithBrainly

8 0
3 years ago
A typical tire for a compact car is 22 inches in diameter. If the car is traveling at a speed of 60 mi/hr, find the number of re
Softa [21]

Answer:

rpm= 916.7436 rev/min

Explanation:

First determine the perimeter of the wheel, to know the horizontal distance it travels in a revolution:

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Time we divide the speed of the car, which is the distance traveled horizontally over time unit, by the perimeter of the wheel that is the horizontal distance traveled in a revolution, this dates us the revolutions over the time unit:

revolutions per time= velocity/perimeter

velocity= (60 mi/hr) × (1609.34m/mi) = 96560m/h

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rpm= (55004.614 rev/hr) × (hr/60min)= 916.7436 rev/min

3 0
4 years ago
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