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DanielleElmas [232]
3 years ago
14

What is the difference between atoms and particals? Help ​

Physics
1 answer:
Otrada [13]3 years ago
7 0

An atom is the smallest unit of matter that forms a chemical element. An atom is made up of three kinds of subatomic particles: electrons, protons, and neutrons.A molecule is a combination of atoms bonded together through a covalent bond. Generally, we think of molecules as having no charge (although molecular ions do exist)

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Suppose one night the radius of the earth doubled but its mass stayed the same. What would be an approximate new value for the f
Alex17521 [72]

Answer:

g' = g/4

Explanation:

  • The value of the free-fall acceleration at the surface of the earth, can be obtained applying Newton's 2nd law, assuming that the only force acting on an object at the surface of the earth, is the one produced by the mass of the Earth, i.e. gravity.
  • This force can be expressed according  the Newton's Universal Law of Gravitation , as follows:

       F_{g} = G*\frac{m_{x} *m_{E} }{r_{E}^{2} }  (1)

  • From Newton's 2nd Law, we have:
  • F = m* a (2)
  • Since the left sides in (1) and (2) are equal each other, both right sides must be equal each other also.
  • Simplifying the mass m, we can write the acceleration a in (2) as the acceleration due to gravity, g, as follows:

       g = G*\frac{m_{E} }{r_{E}^{2} }  (3)

  • Since G is an universal constant, and the mass mE remains constant, if we double the radius of  the Earth, the new value for the acceleration due to gravity (let's call it g'), is as follows:

        g' = G*\frac{m_{E} }{(2r_{E})^{2} } =G*\frac{m_{E} }{4*r_{E}^{2} }  = g*\frac{1}{4}  =\frac{g}{4} (4)

4 0
3 years ago
A 0.850 kg block is attached to a spring with spring constant 18 N/m . While the block is sitting at rest, a student hits it wit
Sveta_85 [38]

The block's speed at the point where x=0.25A is v = 31.95 cm/s.

<h3>What is Spring constant?</h3>

The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies. The stiffer the spring is and the harder it is to stretch, the bigger the spring constant.

question is incomplete, this is the remaining statement

What is the amplitude of the subsequent oscillations? And What is the block's speed at the point where x=0.25A?

x = Asin(wt)

v = Aw coswt

at t = 0

w = sqrt(k/m)

v = Aw

A = v/w

A = 7.17 cm

part b )

E = 1/2mv^2 + 1/2kx^2 = 1/2kA^2

mv^2 + k(1/4A)^2 = 1/2kA^2

mv^2 + kA^2/16 = kA^2

mv^2 = kA^2 - kA^2/16

mv^2 = 15kA^2/16

v^2 = 15/16 * (k/m) * A^2

v^2 = 15/16 *w^2A^2

v = sqrt(15/16) * wA

v = 31.95 cm/s

to learn more about spring constant go to -

brainly.com/question/23885190

#SPJ4

8 0
2 years ago
Determine el valor del ángulo de tiro de un proyectil que tarda en impactar en 8s y que tuvo un alcance de 0,3km.
Gelneren [198K]

Answer:

46.3^{\circ}

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform motion along the horizontal direction (constant velocity)

- A uniformly accelerated motion along the vertical direction (constant acceleration)

The time of flight of a projectile is given by

t=\frac{2u_y}{g}

where

u_y is the initial vertical velocity

g=9.8 m/s^2 is the acceleration due to gravity

Here the time of flight is

t = 8 s

So, the initial vertical velocity is:

u_y=\frac{gt}{2}=\frac{(9.8)(8)}{2}=39.2 m/s

At the same time, the horizontal distance covered by the projectile is given by

d=u_x t

where

u_x is the horizontal velocity, which is constant

t is the time of flight

Here we know that the range of the projectile is 0.3 km, so

d = 0.3 km = 300 m

So the horizontal velocity is

u_x=\frac{d}{t}=\frac{300}{8}=37.5 m/s

Therefore, we can find the angle of projection of the projectile by using:

\theta=tan^{-1}(\frac{u_y}{u_x})=tan^{-1}(\frac{39.2}{37.5})=46.3^{\circ}

5 0
3 years ago
Helpppppp please!!!!!
Mice21 [21]

Answer:

6

Explanation:

7 0
3 years ago
Read 2 more answers
How is wavelength related to a waves energy?
andreyandreev [35.5K]

Answer:

The energy of a wave is directly proportional to its frequency, but inversely proportional to its wavelength. In other words, the greater the energy, the larger the frequency and the shorter (smaller) the wavelength.

Explanation:

i hope it will help u buddy✅

8 0
3 years ago
Read 2 more answers
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