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weqwewe [10]
4 years ago
6

Which law states that a charge cannot be created or destroyed?. A. Law of Conservation of Charge . B. Law of Conservation of Mot

ion . C. Ohm's law . D. Law of Conservation of Energy
Physics
1 answer:
Sedbober [7]4 years ago
7 0
The correct answer for the given question above would be option D. The law that states that a charge cannot be created nor destroyed is the Law of Conservation of Energy. The Law of Conservation of Energy s<span>tates that the total amount of energy in an isolated system remains constant over time. Therefore, it can never be created nor destroyed.</span>
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The Newton is the SI unit for ____.<br> temperature<br> mass<br> weight<br> density
mel-nik [20]

Answer:

weight

Explanation:

weight is measurd in newtons (N)

7 0
3 years ago
Please help!!
pantera1 [17]

Answer:

(a) The time the ball stays in the air is approximately 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is approximately 83.18 meters

(c) The maximum altitude of the ball is approximately 26.62 m

Explanation:

The given parameters of the question are;

The initial velocity at which a baseball cannon fires balls, u = 29 m/s

The angle at which the cannon is tilted, θ = 52°

(a) The time duration the ball stays in the air is given by the time of flight of the projected ball as follows;

2 \cdot t = \dfrac{2 \cdot u \cdot sin (\theta)}{g}

Where;

t = The time it takes the baseball to reach maximum height

2·t = The total time of flight = The time the ball stays in the air

θ = The angle at which the ball is tilted = 52°

g = The acceleration due to gravity ≈ 9.81 m/s²

u = The initial velocity = 29 m/s

Therefore, we have;

2 \cdot t = \dfrac{2 \times 29 \ m/s\times sin (52^{\circ})}{9.81 \ m/s^2} \approx 4.66 \ s

The time the ball stays in the air, 2·t ≈ 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is given by the horizontal range, 'R', of the projectile as follows;

Horizontal \ range, R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}

∴ The distance from the cannon at which the ball will hit the ground = R

Horizontal \ range, R = \dfrac{(29 \ (m/s))^2 \cdot sin(2 \times 52^{\circ}) }{9.81 \ m/s^2} \approx 83.18 \, m

The distance from the cannon at which the ball will hit the ground = R ≈ 83.18 meters

(c) The maximum altitude of the ball is equal to the maximum height reached by the ball, H, which is given as follows;

H = \dfrac{u^2 \cdot sin^2 (\theta)}{2 \cdot g}

Therefore, we have;

H = \dfrac{(29 \ m/s)^2 \times sin^2 (52^{\circ})}{2 \times 9.81 \ m/s^2} \approx 26.62 \ m

The maximum altitude of the ball ≈ 26.62 m

3 0
3 years ago
Mr. and Mrs. Tew attended this summer band concert to her their son play his violin. When they sat down in their seats, they not
Setler [38]
A. They cancelled each other out
3 0
4 years ago
Read 2 more answers
At high pressures, what two factors will cause deviations during ideal gas law calculations?
Tju [1.3M]

At high pressures, the two factors that cause deviation during ideal gas law calculation are the size of molecular and intermolecular force.

The high pressure causes the molecules to approach each other at a very close distance. In that case, if the intermolecular force of attraction is high, the molecules may undergo a state transition, which will result in a completely different outcome as predicted by Ideal gas law.

If the size of the molecule is more, that is for heavy gases like refrigerants, the ideal gas law deviates due to the fact that, with increase in pressure, the volume of gas can no longer be considered as negligible.

To know more about intermolecular force go here

brainly.com/question/9007693

#SPJ4

4 0
2 years ago
Three identical train cars, coupled together, are rolling east at speed v0. A fourth car traveling east at 2v0 catches up with t
aliina [53]

Answer:v_o

Explanation:

It is given that three cars has same mass m with speed v_o

suppose rest two cars also has same mass m

As there is no external force therefore momentum is conserved

Initial Momentum P_i

P_i=3mv_0+m(2v_0)+m\times 0

Final momentum P_f

P_f=5m\times v

where v=final velocity

P_i=P_f

5mv_o=5mv

v=v_o

thus final velocity is v_o

8 0
4 years ago
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