All categories

3 years ago

HELP ASSAP WITH THIS QUESTION 40 POINTS

Mathematics

2 answers:

zhuklara [117]3 years ago

7 0

7x+2y=2

steps:
y+21=-7/2x(x-6)
y+21=-7/2x+21
y=-7/2x+21-21
y=-7/2x
7/2x+y=0
2(7/2x+y=0)
7x+2y=2

zavuch27 [327]3 years ago

3 0

Answer:

7x+2y=2

Step-by-step explanation:

7x+2y=2

y+21=-7/2x(x-6)

y=-7/2x+21-21

2(7/2x+y=0)

7x+2y=2

You might be interested in

Which word could describe the relationship of the lines containing the points (1, 6) and (1, 3)?

Elan Coil [88]

Answer:

Coincidental

Step-by-step explanation:

If the two lines have the same two points, they must also have the same slope and the same y intercept. From this we can deduct that they are actually the same line. Two lines that are directly on top of each other are considered coincidental lines.

3 0

3 years ago

Consider U = {x\x is a real number}

zysi [14]

Answer:

The fourth pair of statement is true.

9∈A, and 9∈B.

Step-by-step explanation:

Given that,

U={x| x is real number}

A={x| x∈ U and x+2>10}

B={x| x∈ U and 2x>10}

5 ∈ A , 5 ∈ B

If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.

Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.

So, 5∉A, and 5∉B.

6 ∈ A , 6 ∈ B

If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.

Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.

So, 6∉A, and 6∈B.

8 ∈ A , 8 ∈ B

If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.

Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.

So, 8∉A, and 8∈B.

9 ∈ A , 9 ∈ B

If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.

Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.

So, 9∈A, and 9∈B.

3 0

3 years ago

What is the equation of the parabola?

Novay_Z [31]

Answer:

The simplest equation for a parabola is y = x^2

3 0

3 years ago

Among the four northwestern states, Washington has 51% of the total population, Oregon has 30%, Idaho has 11%, and Montana has 8

morpeh [17]

Answer:

Step-by-step explanation:

H₀ : The distribution of the sample agrees with the population distribution.

H₁ : the distribution of the does not agree with the population distribution.

Using the Chi-square test statistics

we will compute the expected frequencies

Now expected frequency for Washington will be

Fe = Npi = 1000×51% = 5100

expected frequency for Oregon

Fe = Npi = 1000×30% = 300

expected frequency for Idaho

Fe = Npi = 1000×11% = 110

expected frequency for Montana

Fe = Npi = 1000×8% = 80

The Chi=square test statistics is;

x² = ∑ [ (Fo - Fe)² / Fe )

now we substitute

Given our Fo ( 450 in Washington, 340 in Oregon, 150 in Idaho, and 60 in Montana) from the question

x² = (450-510)²/510 + (340-300)²/300 + (150-110)²/110 + (60-80)²/80

x²= 31.9376

so the chi-square test statistics is 31.9376

Now the chi-square critical value

first we compute for degree of freedom

d.f = k -1 = 4 - 1 = 3

So from the critical value table, degree of freedom 3 and significance level 0.05,

the chi-square critical value is 7.8147

Therefore chi-square test statistics 31.9376 is greater than the chi-square critical value 7.8147, so NULL HYPOTHESIS IS REJECTED at 5% significance.

There is sufficient evidence to warrant rejection of the claim that the distribution of the sample agrees with the distribution of the state populations.

3 0

3 years ago

Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g

Ilia_Sergeevich [38]

a. The $\vec k$ component tells you the particle's height: