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Black_prince [1.1K]
3 years ago
10

Help me!!!!!!!!!plzzz​

Mathematics
2 answers:
Anika [276]3 years ago
6 0

Answer:

1/3

Step-by-step explanation:

add all the values 10+14+6=30 since red is 10 divide 10 by 30 so 10/30 simplifying to 1/3.

RSB [31]3 years ago
5 0

Answer:

B. 1/3

Step-by-step explanation:

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What’s the answer???
Phantasy [73]

Answer:

16 over 19

Step-by-step explanation:

they both equal the same number

3 0
3 years ago
A bag with 2 2/4 ounces of peanuts can make 2/3 of a jar of peanut butter. It can make one full jar with how many ounces of pean
lbvjy [14]
One whole jar= 3/3 or 1

Set up a ratio comparing the two sets of measurements.

2 2/4 ounces of peanuts is to 2/3 of a jar as x ounces of peanuts is to 3/3 of a jar.

x= ounces in 1 whole jar

2 2/4 / 2/3= x / 3/3
cross multiply

(2 2/4 * 3/3)= (2/3 * x)
convert to improper fractions

10/4 * 3/3= 2/3x
multiply numerators; multiply denominators

(10*3)/(4*3)= 2/3x

30/12= 2/3x
divide both sides by 2/3

30/12 ÷ 2/3= x
to divide fractions, multiply by the reciprocal/inverse of 2/3

30/12 * 3/2= x
multiply numerators; multiply denominators

(30*3)/(12*2)= x
90/24= x
simplify by 6

15/4 or 3 3/4 ounces= x


ANSWER: 3 3/4 ounces can make a full jar.

Hope this helps! :)
5 0
3 years ago
QUESTION 6 Find the 20th term of the sequence. 1600, 1200, 900, ...
almond37 [142]

Answer:

9.02 B .......

Step-by-step explanation:

because I'm not really sure but that's an answer

5 0
2 years ago
For f(x)=0.01(2)power of x, find the average rate of change from x=3 to x=8
sineoko [7]
\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= 0.01(2)^x  \qquad 
\begin{cases}
x_1=3\\
x_2=8
\end{cases}\implies \cfrac{f(8)-f(3)}{8-3}
\\\\\\
\cfrac{0.01(2)^8-0.01(2)^3}{8-3}
4 0
3 years ago
Rewrite 3^-4 without negative exponents
KengaRu [80]

Answer:

\frac{1}{3^{4} }

Step-by-step explanation:

5 0
2 years ago
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