3 years ago

Just need to check these answers

1 answer:

amid [387]3 years ago

3 0

Great Job! they are all correct. :)

Good luck in your next tests.

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aleksklad [387]

4.43
4 1/2
4.504
113/25

8 0

3 years ago

daser333 [38]

Answer:

B. 1/2

Step-by-step explanation:

$\lim_{z \to 0} \frac{g(z)e^{-z}-3}{z^{2}-2z}$

If we plug in 0 for z, we get 0/0. Apply l'Hopital's rule.

$\lim_{z \to 0} \frac{-g(z)e^{-z}+g'(z)e^{-z}}{2z-2}$

Now when we plug in 0 for z, we get:

$\frac{-g(0)e^{0}+g'(0)e^{0}}{2(0)-2}\\\frac{-g(0)+g'(0)}{-2}\\\frac{-3+2}{-2}\\\frac{1}{2}$

4 0

3 years ago

inysia [295]

0.45 = 45/100
45/100 = 9/20 (Simplified)

8 0

4 years ago

saveliy_v [14]

Option C is correct.

$70000 \times 15 \times 5 \div 100 \\ \\$
SI =P×R×T÷100

8 0

3 years ago

maw [93]

Answer:

8:10 and 12: 15

Step-by-step explanation:

we have to multiply

5 0

3 years ago