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mylen [45]
3 years ago
12

Wich substances is most likely to form in a precipitation reaction?

Chemistry
1 answer:
Flura [38]3 years ago
4 0

Answer:

A precipitation reaction refers to the formation of an insoluble salt when two solutions containing soluble salts are combined. The insoluble salt that falls out of solution is known as the precipitate, hence the reaction's name.

Explanation:

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What is the pressure of the ideal gas when the volume is decreased to 4.0 L and the temperature is increased to 265 K?
jonny [76]
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3 years ago
In the compound 5Cr2O3 the 5 represents
Liono4ka [1.6K]

Answer:

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Read 2 more answers
A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate th
Andreas93 [3]

Complete question:

A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate the heat of combustion of methanol in kJ/mol.

Answer:

the heat of combustion of the methanol is 402.31 kJ/mol

Explanation:

Given;

mass of water, m_w = 100 g

initial temperature of water, t₁ = 28 ⁰C

final temperature of water, t₂ = 58 ⁰C

specific heat capacity of water = 4.184 J/g⁰C

reacting mass of the methanol, m = 1.00 g

molecular mass of methanol = 32.04 g/mol

number of moles = 1 / 32.04

                             = 0.0312 mol

Apply the principle of conservation of energy;

n\Delta H_{methanol} = Q_{water}\\\\n\Delta H_{methanol} =  mc\Delta t\\\\n\Delta H_{methanol} =  100 \times 4.184\times (58-28)\\\\n\Delta H_{methanol} =  12,552 \ J\\\\n\Delta H_{methanol} =  12.552 \ kJ\\\\\Delta H_{methanol} = \frac{12.552}{n} \\\\H_{methanol} = \frac{12.552 \ kJ}{0.0312 \ mol} \\\\\Delta H_{methanol} = 402.31 \ kJ/mol

Therefore, the heat of combustion of the methanol is 402.31 kJ/mol

                       

5 0
3 years ago
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