Question

Lactic acid has a pKa of 3.08. What is the approximate degree of dissociation of a 0.35 M solution of lactic acid?

Answer 1

The approximate degree of dissociation of a 0.35 M solution of lactic acid is 4,87%

What is  degree of dissociation?

The degree of dissociation is the quantity used to express the strength of a base, that is, its ability to conduct electric current, which depends on the amount of ions released in the dissociation.

The degree of dissociation (α) is another way of determining the strength of a base. It indicates the fatty acids that were released from a base when it dissociates in water.

With that being said, C stands for concentration and α is the the degree of dissociation.

Latic Acid can be written as  C3H6O3

$CH3Ch(OH)CO2H < -- > H^{+} + CH3CH(OH)CO2^{-}$

$Ka = \frac{[H^{+}] [CH3CH(OH)CO2^{-}] }{CH#CH(OH)CO2H} = \frac{C^{2} \alpha^{2} }{C(1-\alpha )} = \frac{C\alpha ^{2} }{(1-\alpha )}$

As α is too small (1-α) can be neglected.

$Ka = C\alpha ^{2} \\\\\\alpha = \sqrt[]{\frac{Ka}{C} }$

$Ka = 10^{-3,08} = 8,32 .10^{-4} .10^{-4} = 0,35$

$\alpha = \sqrt{\frac{ka}{C} } \\\\\alpha = \sqrt{\frac{8,32.10^{-4} }{0,35} } = 0,0487$

In this case, is possible to see that  approximate degree of dissociation of a 0.35 M solution of lactic acid is 4,87%

See more about pKa at: brainly.com/question/14924722

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