Answer:
Partial pressure of Ar = 4.7 atm
Explanation:
Total pressure of a mixture of gases = Sum of partial pressure of each gas
This mixture contains: O₂, He and Ar.
Total pressure = 15.3 atm
Total pressure = Partial pressure O₂ + Partial pressure of He + Partial pressure of Ar
15.3 atm = 7.4 atm + 3.2 atm + Partial pressure of Ar
Partial pressure of Ar = 15.3 atm - 7.4 atm - 3.2 atm
Partial pressure of Ar = 4.7 atm
Answer:
3.38 moles.
Explanation:
The following data were obtained from the question:
Mass of copper (Cu) = 215 g
Number of mole of copper (Cu) =...?
The number of mole of copper (Cu) in 215 g can be obtained as follow:
Mass of copper (Cu) = 215 g
Molar mass of copper (Cu) = 63.55 g/mol
Number of mole of copper (Cu) =...?
Mole = mass /Molar mass
Mole of Cu = 215/63.55
Mole of Cu = 3.38 moles
Therefore, 3.38 moles of copper (Cu) is present in the sample.
You need to use q = mc(delta t)
<span>Solve for c: </span>
<span>c = q / m(delta t) </span>
<span>q = 55.o J </span>
<span>m = 11.0 g </span>
<span>delta t = 24.5 - 13.0 = 11.5 deg C </span>
<span>c = 55 J / 11.0 g)(11.5 C) </span>
<span>c = 0.435 J/ g C</span>
Answer:522.93 centimeters
Explanation:
I calculated the numbers
