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2 years ago

How many moles of Al are needed to react completely with 1.2 moles of Fe0

Chemistry

1 answer:

DIA [1.3K]2 years ago

7 0

0.8 moles

3 moles of feO gives you 2 moles of Al and 1.2 of your moles should give you 1.2 divided by 3*2 so it equals 0.80 moles

Right?

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dalvyx [7]

The stoichiometry of the reaction gives the molar ratio in which the reactants react with each other and the ratio in which products are formed.
The coefficients of the reactants in the reaction follow the stoichiometry
the balanced chemical equation for the reaction is as follows;
2C₃H₆(g) + 9O₂(g) ---> 6CO₂(g) + 6H₂O(l)

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3 years ago

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Which measurement, temperature or volume, limits the precision of the data obtained in the experiment? explain?

GrogVix [38]

The answer is volume that is volume limits the precision of data obtained in an experiment .

As while pouring of the liquids, we control the volume, but it can have been off. And this could results in the wrong mole to mole ratio.Thus it limits the precision, So the answer is that volume limits the precision of data obtained in an experiment .

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3 years ago

At 273 k and 1.00 x 10^-2 atm, the density of a gas is 1.24 x 10^-5 g/cm3.

bija089 [108]

Root mean square velocity is the square root of the mean of the squares of speeds of different molecules. From kinetic theory of gas, the formula of root mean square velocity=C $_{rms}$ = √ $\frac{3RT}{M}$ =√ $\frac{3PV}{M}$ =√ $\frac{3P}{d}$ , where, R= Universal gas constant, T= Absolute temperature, P= Pressure, V= Volume of gas, d= Density of gas.

Given, T=273 K, P=1.00 x 10⁻² atm, d=1.24 x 10⁻⁵ g/cm³.

(a) Using the formula $C_{rms}$ =√ $\frac{3P}{d}$ =√(3X1.00X10⁻²)/(1.24X10⁻⁵)=49.18

(b) Molar mass can be determined by using the formula $C_{rms}$ =√{3RT}{M}

49.18=√ $\frac{3X8.314X273}{M}$

49.18²=√(3X8.314X273)/M

M= $\frac{3X8.314X273}{49.18^{2} }$

M=1.67 ≅ 2

Molecular mass is 2.

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2 years ago

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Scientists utilize models for a variety of different purposes, but each type of scientific model has limitations. What might be

Nezavi [6.7K]

They are based in current knowledge

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3 years ago

A child has a toy balloon with a volume of 1.80 L. The temperature of the balloon when it was filled was 293 K at a pressure of

Mekhanik [1.2K]

Answer:

2.42L

Explanation:

Given parameters:

V₁ = 1.8L

T₁ = 293K

P₁ = 101.3kPa

P₂ = 67.6kPa

T₂ = 263K

Unknown:

V₂ = ?

Solution:

To solve this problem, we are going to use the combined gas law to find the final volume of the gas. The combined gas law expression combines the equation of Boyle's law, Charles's law and Avogadro's law;

$\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }$

All the units are in the appropriate form. We just substitute and solve for the unknown;

101.3 x 1.8 / 293 = 67.6 x V₂ / 263

V₂ = 2.42L

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2 years ago