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Degger [83]
3 years ago
10

What is the volume of an object with a mass of 31g and density of 444g/ml​

Chemistry
1 answer:
Tanzania [10]3 years ago
5 0

Answer:

<h2>The answer is 0.07 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 31 g

density = 444 g/mL

We have

volume =  \frac{31}{444}   \\  = 0.06981...

We have the final answer as

<h3>0.07 mL</h3>

Hope this helps you

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Th e molar absorption coeffi cients of tryptophan and tyrosine at 240 nm are 2.00 × 103 dm3 mol−1 cm−1 and 1.12 × 104 dm3 mol−1
nataly862011 [7]

Answer:

5.43x10⁻⁵ dm³mol⁻¹= Concentration of tyrosine

2.58x10⁻⁵ dm³mol⁻¹= Concentration of tryptophan

Explanation:

Lambert-Beer law is:

A = E×C×l

Where A is measured absorbance, E is absorption coefficient, C is concentration of solution and l is optical path length.

For the result at 240nm, it is possible to write:

0.660 = 2.00x10³ dm³mol⁻¹cm⁻¹× Ctry × 1cm + 1.12x10⁴ dm³mol⁻¹cm⁻¹× Ctyr × 1cm <em>(1)</em>

At 280 nm:

0.221 = 5.40x10³ dm³mol⁻¹cm⁻¹× Ctry × 1cm + 1.50x10³ dm³mol⁻¹cm⁻¹× Ctyr × 1cm <em>(2)</em>

<em></em>

Thus:

-2.7× (0.660 = 2.00x10³ × Ctry  + 1.12x10⁴ × Ctyr) =

-1.782 = -5.40x10³Ctry - 3.024x10⁴Ctyr

0.221 = 5.40x10³ × Ctry + 1.50x10³  × Ctyr

-------------------------------------------------------------------

-1.561 = -28740×Ctyr

<em>5.43x10⁻⁵ dm³mol⁻¹= Ctyr</em>

Replacing this value in (1) or (2) it is possible to find Ctry, that is:

<em>2.58x10⁻⁵ dm³mol⁻¹= Ctry</em>

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