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Thepotemich [5.8K]
3 years ago
14

Use the drop-down menus to complete the statements.

Physics
2 answers:
yaroslaw [1]3 years ago
7 0

Answer:

Experimental

Descriptive

Comparative

Explanation:

I just finished the test.

MaRussiya [10]3 years ago
4 0

Answer:

1- experimental

2-descriptive

3-comparative

Explanation:

just did it

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51. Suppose you measure the terminal voltage of a 3.200-V lithium cell having an internal resistance of 5.00Ω by placing a 1.00-
Tanya [424]

Explanation:

Given that,

Terminal voltage = 3.200 V

Internal resistance r= 5.00\ \Omega

(a). We need to calculate the current

Using rule of loop

E-IR-Ir=0

I=\dfrac{E}{R+r}

Where, E = emf

R = resistance

r = internal resistance

Put the value into the formula

I=\dfrac{3.200}{1.00\times10^{3}+5.00}

I=3.184\times10^{-3}\ A

(b). We need to calculate the terminal voltage

Using formula of terminal voltage

V=E-Ir

Where, V = terminal voltage

I = current

r = internal resistance

Put the value into the formula

V=3.200-3.184\times10^{-3}\times5.00

V=3.18\ V

(c). We need to calculate the ratio of the terminal voltage of voltmeter equal to emf

\dfrac{Terminal\ voltage}{emf}=\dfrac{3.18}{3.200 }

\dfrac{Terminal\ voltage}{emf}= \dfrac{159}{160}

Hence, This is the required solution.

5 0
3 years ago
the wattage ratting of a light bulb is the power it sonsumers when it is connected accross a 120 V potential difference what is
igor_vitrenko [27]

Answer:

240 Ω

Explanation:

Resistance: This can be defined as the opposition to the flow of current in an electric field. The S.I unit of resistance is ohms (Ω).

The expression for resistance power and voltage is give as,

P = V²/R.......................... Equation 1

Where P = Power, V = Voltage, R = Resistance

Making R the subject of the equation,

R = V²/P.................... Equation 2

Given: V = 120 V, P = 60 W.

Substitute into equation 2

R = 120²/60

R = 240 Ω

Hence the resistance of the bulb = 240 Ω

8 0
3 years ago
The spool has a mass of 50 kg and a radius of gyration of ko = 0.280 m. if the 20-kg block a is released from rest, determine th
Rzqust [24]
V₁ = (1/g)₁ = Way₁ = 20(9.81)(0) = 0
V₂ (Vg)₂ = -WAy₂ = -20(9.81)(0.5) = -98.1J
The kinetic energy because the pool rotates about a fixed axis 
W = VA/rA = VA/0.2 5VA
Mass momen of inertila about fixed axis which passes through point 0
I₀ = mko² = 50(0.280)² = 3.92 kg. m²
∴ The kinetic energy of the system is 
T = 1/2 I₀w² + 1/2mAVA²

= 1/2(3.92)(5VA)² + 1/2 (20) VA² = 59VA²
Now that the system is at rest then T₁ = 0
Energy conservation  is
T₁ +V₁ = T₂ + V₂
0+ 0 = 59VA² + (-98.1)
VA = 1.289 m/s
= 1.29 m/s
5 0
3 years ago
1 point
White raven [17]

Answer:

Waves transfer energy, not motion

8 0
3 years ago
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What percent of the world lumber harvest goes to paper production<br> 10%<br> 20%<br> 25%<br> 50%
sergejj [24]
The answer is 50% of the paper production
8 0
3 years ago
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