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larisa [96]
3 years ago
10

Two capacitors give an equivalent capacitance of 9.42 pF when connected in parallel and an equivalent capacitance of 1.68 pF whe

n connected in series. What is the capacitance of each capacitor?
Physics
1 answer:
gavmur [86]3 years ago
5 0

Answer:

C_1=7.23pF\ and\ C_2=2.19pF

Explanation:

Let the two capacitance are C_1\ and\ C_2

It is given that when capacitors are connected in parallel their equvilaent capacitance is 9.42 pF

So C_1+ C_2=9.2--------EQN 1

And when they are connected in series their equivalent capacitance is 1.68 pF

So \frac{1}{C_1}+\frac{1}{C_2}=\frac{1}{1.68}

\frac{C_1+C_2}{C_1C_2}=\frac{1}{1.68}

C_1C_2=1.68\times 9.42=15.8256pF

C_1-C_2=\sqrt{(C_1+C_2)^2-4C_1C_2}=\sqrt{9.42^2-4\times 15.8256}=5.0432pF-----EQN

On solving eqn 1 and eqn 2

C_1=7.23pF\ and\ C_2=2.19pF

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Answer:

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Explanation:

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       K_{trans} = \frac{1}{2}* M* v_{cm} ^{2}  (1)

  • The rotational part can be expressed as follows:

       K_{rot} = \frac{1}{2}* I* \omega ^{2}  (2)

  • where I = moment of Inertia regarding the axis of rotation.
  • ω = angular speed of the rotating object.
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       v = \omega * R (3)

  • For a solid cylinder, I = M*R²/2 (4)
  • Replacing (3) and (4)  in (2), we get:

       K_{rot} = \frac{1}{2}* \frac{1}{2} M*R^{2} * \frac{v_{cmc} ^{2}}{R^{2}} = \frac{1}{4}* M* v_{cmc}^{2}  (5)

  • Adding (5) and (1), we get the total kinetic energy for the solid cylinder, as follows:

       K_{cyl} = \frac{1}{2}* M* v_{cmc} ^{2}  +\frac{1}{4}* M* v_{cmc}^{2}  =  \frac{3}{4}* M* v_{cmc} ^{2} (6)

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        I_{sph} = \frac{2}{3} * M* R^{2} (7)  

       K_{rot} = \frac{1}{2}* \frac{2}{3} M*R^{2} * \frac{v_{cms} ^{2}}{R^{2}} = \frac{1}{3}* M* v_{cms}^{2}  (8)

      K_{sph} = \frac{1}{2}* M* v_{cms} ^{2}  +\frac{1}{3}* M* v_{cms}^{2}  =  \frac{5}{6}* M* v_{cms} ^{2} (9)

  • Since we know that both masses are equal each other, we can simplify (6) and (9), cancelling both masses out.
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An apple falls out of a tree from a height of 2.3m. what is the impact speed of the apple
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Answer:6.71 m/s

Explanation:

Given

Apple fall from a height of h=2.3 m  

We need to find the impact speed of apple which can be given by using

v^2-u^2=2gh  

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Assuming initial velocity to be zero

substituting the value we get

v^2-0=2\times 9.8\times 2.3  

v=\sqrt{2\times 9.8\times 2.3}  

v=6.71\ m/s  

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Hello
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A car of mass 1535 kg collides head-on with a parked truck of mass 2000 kg. Spring mounted bumpers ensure that the collision is essentially elastic. If the velocity of the truck is 17 km/h (in the same direction as the car's initial velocity) after the collision, what was the initial speed of the car <u>20kmh</u>

<h3>What is collision ?</h3>

A collision in physics is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.

The following are a few instances of physical encounters that scientists might classify as collisions:

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To learn more about collision  from the given link:

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