A small summary of the 4 areas can be described as:
<em>Location: </em>The tradition of location tries to explain the course of human settlements in terms of location, growth and in relation to other premises.
<em>Area analysis tradition</em> determine as much as possible to obtain information about a particular place to define, describe and differentiate it from other regions or areas.
<em>Culture-environment tradition</em> is the study of the relationship between human beings and the land in which they live. Culture-environment not only analyzes the impact that people impose on their local environment, but, on the contrary, how natural hazards can influence human life.
<em>Earth Science Tradition</em> is the study of planet Earth as the home of humans and their systems. Along with the physical geography of the planet, the study approaches include things like how the location of the planet in the solar system affects its seasons (this is also known as Earth-Sun interaction) and how changes in the lithosphere, hydrosphere, atmosphere and Biosphere impacts human life on the planet.
Therefore the correct answer is B.
Answer:
A. Both spheres land at the same time.
Explanation:
The horizontal motion doesn't affect the vertical motion. Since the two spheres have the same initial vertical velocity and same initial height, they land at the same time.
2Ω. Based on the graph the resistance of the bulb is 2Ω.
Based on the graph of the image we can see there are a linear proportionality between the voltage and the current. So, we can modeling this problem calculating the slope of the straight line in the graph as follow:
We can write a formula of the form .
From the Ohm's Law we know that the resistance is directly proportional to the voltage and inversely proportional to the current .
From the graph we can see in the x-axis the values of the voltage and the y-axis the value of the current, with the points (x, y) = (2, 1) and (x₁, y₁) = (4, 2) marked in the graph, we can write:
We need to express the equation in the form :
R = 2Ω