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3 years ago

Which of the following best represents the speed of Halley's comet when it is nearest to Earth?

Physics

2 answers:

trasher [3.6K]3 years ago

5 0

Answer:

d. $1 \times 10^{5}$ kilometers per hour

Explanation:

Halley's comet is named after the astronomer Halley. This comet entered the inner solar system from the Kupier's belt. It is very large in size. It appears every 75 or 79 years in the inner solar system and can be seen with the naked eye. Its orbit is elliptical in shape. It reflects the sun light, otherwise it is entirely dark and made up of volatile material, as observed

Gre4nikov [31]3 years ago

3 0

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Among the choices provided above the one that best represents the speed of Halley's comet when it is nearest to Earth is letter D which is <span>1 × 10^5 kilometers per hour. </span>

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Answer:

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2 years ago

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A student team is to design a human powered submarine for a design competition. The overall length of the prototype submarine is

Allushta [10]

Answer:

a) The speed is 61.42 m/s

b) The drag force is 10.32 N

Explanation:

a) The Reynold´s number for the model and prototype is:

$Re_{m} =\frac{p_{m}V_{m}L_{m} }{u_{m} }$

$Re_{p} =\frac{p_{p}V_{p}L_{p} }{u_{p} }$

Equaling both Reynold's number:

$\frac{p_{p}V_{p}L_{p} }{u_{p} }=\frac{p_{m}V_{m}L_{m} }{u_{m} }$

Clearing Vm:

$V_{m} =\frac{p_{p}V_{p}L_{p} u_{m} }{u_{p} p_{m} L_{m} }=\frac{999.1*0.56*8*1.849x10^{-5} }{1.138x10^{-3}*1.184*1 } =61.42m/s$

b) The drag force is:

$\frac{F_{Dm} }{p_{m}V_{m}^{2}L_{m}^{2} } =\frac{F_{Dp} }{p_{p}V_{p}^{2}L_{p}^{2} } \\F_{Dp} =\frac{F_{Dp}p_{p}V_{p}^{2}L_{p}^{2} }{p_{m}V_{m}^{2}L_{m}^{2} } \\F_{Dp}=\frac{2.3*999.1*0.56^{2} *8^{2} }{1.184*61.42^{2}*1^{2} } =10.32N$

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2 years ago

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A classmate is attempting to draw a free body diagram for a box being pushed across the floor at a constant speed. The image bel

aivan3 [116]

Answer:

A. The applied force should be the same size as the friction force

Explanation:

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<u>A. The applied force should be the same size as the friction force</u>

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2 years ago

Suppose that a teacher driving a 1972 LeMans zooms out of a darkened tunnel at 34.5 m/s. He is momentarily blinded by the sunshi

valkas [14]

Answer:

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Explanation:

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t=13.8-0.31s=13.49s

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$x=vt=(15.1m/s)(13.49s)=203.69m$ (1)

Next you calculate the distance that teacher has traveled for 13.6s:

$x=x_o+v_ot+\frac{1}{2}at^2\\\\x=0m+34.5m/s(13.49s)+\frac{1}{2}(2.5m/s^2)(13.49s)^2=692.88m$ (2)

The minimum distance between the driver and the camper will be the difference between (2) and (1):

$x_{min}=692.88m-203.69m=489.19m$

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3 years ago

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djyliett [7]

Answer:

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Explanation:

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