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tankabanditka [31]
3 years ago
9

When 1.5 mol calcium nitrate dissolves in water, how many moles of ions should be present in solution?

Chemistry
1 answer:
____ [38]3 years ago
5 0

Answer:

1.5 moles of Ca²⁺ and 3 moles of NO₃⁻

Explanation:

This is the dissociation:

Ca(NO₃)₂  →  Ca²⁺  +  2NO₃⁻

1.5 moles of salt will have the same moles of ion Ca²⁺ and the double of moles, of nitrate according to the equation.

Therefore will be 1.5 moles of Ca²⁺ and 3 moles of NO₃⁻

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Answer:

C₆H₁₂O₆ and O₂ are reactant.

CO₂ and H₂O are products.

C₆H₁₂O₆ + 6O₂  →  6CO₂ + 6H₂O + ATP

Explanation:

There are two types of respiration:

1. Aerobic respiration  

2. Anaerobic respiration

Aerobic respiration

It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

Anaerobic Respiration

It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.  

Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide

This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.

Steps involve in anaerobic respiration are:

Glycolysis

Glycolysis is the first step of both aerobic and anaerobic respiration. It involve the breakdown of one glucose molecule into pyruvate and 2ATP.

Fermentation

The second step of anaerobic respiration is fermentation. It involve the fermentation of pyruvate into lactic acid or alcohol depending upon the organism in which it is taking place. There is no ATP produced, however carbon dioxide is released in this step.

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<span>fragmentation that is the answer</span>
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Answer ; The question is missing in some details, but here are he details ;

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Explanation:

The detaile calculation is as shown in the attachment.

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