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nata0808 [166]
3 years ago
11

What percentage of the mass of 1 mole of CH3Cl is derived from carbon?​

Chemistry
1 answer:
steposvetlana [31]3 years ago
3 0

Answer:

Element Symbol Atomic weight Atoms Mass percent

Carbon C                  12.0107               1              23.7894

Hydrogen H         1.00794                3         5.9892

Chlorine Cl                 35.453                 1       70.2213

Explanation:

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Two different proteins X and Y are dissolved in aqueous solution at 37 °C. The proteins bind in a 1:1 ratio to form XY. A soluti
aleksklad [387]

Answer:

Kc of reaction is 20.

Explanation:

The two proteins are X and Y.

The [X] = 1mM

[Y]=1mM

At equilibrium, [X] = 0.2mM  [Y] = 0.2mM

we know that equilibrium constant is:

Kc=\frac{[Products]}{[Reactants]}=\frac{[XY]}{[X][Y]}

[XY]= 1-0.20=0.80 mM

putting values:

Kc=\frac{0.80}{0.20X0.20}=20

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2 years ago
Determine a massa de um átomo de carbono12 em gramas
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I believe it would be 1.660539040 × 10−24 gram.
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2 years ago
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Maricruz prepared 450 ml of 0.0085 M solution of sodium chloride. How many grams of NaCl did she need to make 0.450 L of 0.0085
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Answer:

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2 years ago
Provide the element name with a ground-state electron configuration of 1s22s2p4
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Oxygen I’m pretty sure
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2 years ago
Calculate the mass of Na2O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reacti
e-lub [12.9K]

Answer:

The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.

Explanation:

You know  the balanced reaction:

4 NA + O₂ ⟶ 2 Na₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:

  • Na: 4 moles
  • O₂: 1 mole
  • Na₂O: 2 moles

Being:

  • Na: 23 g/ole
  • O: 16 g/mole

the molar mass of the compounds participating in the reaction is:

  • Na: 23 g/mole
  • O₂: 2*16 g/mole= 32 g/mole
  • Na₂O: 2*23 g/mole +16 g/mole=  62 g/mole

Then by stoichiometry of the reaction they react and are produced:

  • Na: 4 moles* 23 g/mole= 92 g
  • O₂: 1 mole*32  g/mole= 32 g
  • Na₂O: 2 moles* 62 g/mole= 124 g

Then you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?

massofNa_{2}O =\frac{4 grams of Na*124 gramsofNa_{2}O }{92 grams of Na}

mass of Na₂O=5.39 g

<em><u>The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.</u></em>

8 0
2 years ago
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