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3 years ago

Runner A is initially 5.3 km west of a flag-

Physics

1 answer:

Alik [6]3 years ago

3 0

4.8 km because if u add the other bonus if speed and multiply you check the 48 taking off a decimal point

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Check the correctness of given equation<br> s = ut + (1/2)at^2

ruslelena [56]

Lets use Dimensional analysis.

$\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2$

$\\ \sf\longmapsto s=\left[M^0LT^0\right]$

$\\ \sf\longmapsto ut+\dfrac{1}{2}at^2$

$\\ \sf\longmapsto \left[M^0LT^{-1}\right]\left[M^0L^0T^1\right]+\dfrac{1}{2}\left[M^0LT^{-2}\right]\left[M^0L^0T^1\right]^2$

$\\ \sf\longmapsto L+\dfrac{1}{2}\left[LT^{-2}\right]\left[T^2\right]$

$\\ \sf\longmapsto L+\dfrac{1}{2}L$

$\\ \sf\longmapsto \dfrac{2L}{2}$

$\\ \sf\longmapsto [L^1]$

$\\ \sf\longmapsto \left[M^0LT^0\right]$

LHS=RHS

Hence verified

6 0

3 years ago

An elevator has a mass of 3000 kg. If the upward tension in the

Liula [17]

Answer: 18 m

Explanation: because it does

7 0

3 years ago

Read 2 more answers

Can y’all please help me with this 3 part question?

klio [65]

Answer:

Vf = 210 [m/s]

Av = 105 [m/s]

y = 2205 [m]

Explanation:

To solve this problem we must use the following formula of kinematics.

$v_{f} =v_{o} +g*t$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (released from the rest)

g = gravity acceleration = 10 [m/s²]

t = time = 21 [s]

Vf = 0 + (10*21)

Vf = 210 [m/s]

Note: The positive sign for the gravity acceleration means that the object is falling in the same direction of the gravity acceleration (downwards)

The average speed is defined as the sum of the final speed plus the initial speed divided by two. (the initial velocity is zero)

Av = (210 + 0)/2

Av = 105 [m/s]

To calculate the distance we must use the following equation of kinematics

$v_{f} ^{2} =v_{o} ^{2} +2*g*y\\\\(210)^{2} = 0 + (2*10*y)$

44100 = 20*y

y = 2205 [m]

5 0

3 years ago

For what visible wavelengths of light do the reflected waves interfere constructively? The range of wavelength of visible light

Otrada [13]

Answer:

None of the wavelength is in the visible range

Explanation:

Constructive interference of the reflected waves for different wavelengths can be estimated using:

λ $_{m}$ = 2nd/m

where m is 1,2,3, ...

Therefore:

m=1, λ $_{1}$ = 750 nm

m=2, λ $_{1}$ = 750/2 = 375 nm

The limits of eye's sensitivity is between 430 nm and 690 nm. Beyond this range, the eye's sensitivity drops to approximately 1% of its maximum value.

7 0

4 years ago

A long, rigid conductor, lying along an x axis, carries a current of 4.99 A in the negative x direction. A magnetic field is pre

Tcecarenko [31]

Answer with Explanation:

We are given that

Current in conductor=I=4.99 A (-x direction)

Magnetic field=B= $3.72\hat{i}+8.72x^2\hat{j}mT=(3.72i+8.72x^2j)\times 10^{-3}$