Answer:
λ = hv
If frequency is doubled :
λ = h × 2v
λ = 2hv
Thus wavelength is doubled
Answer:
Resonance depends on objects, this may happen for example when you play guitar in a given room, you may find that for some notes the walls or some object vibrate more than for others. This is because those notes are near the frequency of resonance of the walls.
So waves involved are waves that can move or affect objects (in this case the pressure waves of the sound, and the waves that are moving the wall).
this means that the waves are mechanic waves.
Now, in electromagnetics, you also can find resonance frequencies for electromagnetic waves trapped in things called cavities, but this is a different topic.
To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.
The intensity of the wave at the receiver is
The amplitude of electric field at the receiver is
The amplitude of induced emf by this signal between the ends of the receiving antenna is
Here,
I = Current
= Permeability at free space
c = Light speed
d = Distance
Replacing,
Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V
Answer:
Neither lma0 I'm from a town :P
Explanation:
Hbu?
Have a nice dayyy <3
