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Doss [256]
4 years ago
15

A solution that has a high concentration of hydrogen ions has what type of pH?

Physics
2 answers:
icang [17]4 years ago
8 0
They're right, it is in fact A:2
Darya [45]4 years ago
4 0
I believe the answer is A.
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To find original research in animal disease prevention, it would be best to consult a/an
yarga [219]
The correct answer that would best complete the given statement above would be PERIODICAL OR TRADE JOURNAL. To find <span>original research in animal disease prevention, it would be best to consult a periodical or trade journal. A trade journal is a journal that contains news of interest about a specific trade. </span>
6 0
3 years ago
When you throw a pebble straight up with initial speed V, it reaches a maximum height H with no air resistance. At what speed sh
aev [14]

Answer:

Explanation:

Given

Initial speed is u=V

Maximum height of Pebble is H

Deriving maximum height of Pebble and considering motion in vertical direction

v^2-u^2=2 as

where v=final velocity

u=initial velocity

a=acceleration

s=Displacement

Final velocity will be zero at maximum height

0-(V)^2=2\times (-g)\cdot H

H=\frac{V^2}{2g}

i.e. maximum height is dependent on square of initial velocity

for twice the height

2H=\frac{(V')^2}{2g}

on comparing

V'=\sqrt{2}V

7 0
3 years ago
A current of 5 A passes through a variable resistor set to 15 Ω. Calculate the voltage
OLEGan [10]

Answer:

75 volt

Explanation:

Current (I) = 5 A

Resistance (R) = 15 Ω

Voltage (V) = ?

We know

R = V/I

15 = v / 5

v = 75 Volt

3 0
3 years ago
Which layer of the atmosphere has the highest density?
fomenos

Answer:

The Troposphere is the lowermost portion of Earth’s atmosphere. It is the densest layer of the atmosphere and contains approximately 75 percent of the mass of the atmosphere and almost all the water vapor and aerosol. The troposphere extends from the Earth’s surface up to the tropopause where the stratosphere begins.

Explanation:

4 0
3 years ago
A block is projected up a frictionless inclined plane with initial speed v0 = 1.72 m/s. The angle of incline is θ = 44.8°. (a) H
Snowcat [4.5K]

Explanation:

Given

initial velocity(v_0)=1.72 m/s

\theta =44.8{\circ}

using v^2-u^2=2as

Where v=final velocity (Here v=0)

u=initial velocity(1.72 m/s)

a=acceleration   (gsin\theta )

s=distance traveled

0-(1.72)^2=2(-9.81\times sin(44.8))s

s=0.214 m

(b)time taken to travel 0.214 m

v=u+at

0=1.72-gsin(44.8)\times t

t=\frac{1.72}{9.8\times sin(44.8)}

t=0.249 s

(c)Speed of the block at bottom

v^2-u^2=2as

Here u=0 as it started coming downward

v^2=2\times gsin(44.8)\times 0.214

v=\sqrt{2.985}

v=1.72 m/s

3 0
3 years ago
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