All categories

3 years ago

A 4 kg bowling bowl is sitting on a table 1 meter off the ground. How much potential energy does it have?

Physics

1 answer:

il63 [147K]3 years ago

5 0

Answer:

$\huge\boxed{\sf P.E. = 39.2\ Joules}$

Explanation:

<u>Given Data:</u>

Mass = m = 4 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 1 m

<u>Required:</u>

Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = mgh

<u>Solution:</u>

P.E. = (4)(9.8)(1)

P.E. = 39.2 Joules

$\rule[225]{225}{2}$

Hope this helped!

You might be interested in

In an experiment, a ringing bell is placed in a vacuum jar that does not have any air in it. What best describes why the bell is

madam [21]

Answer:

Light does not need a medium to travel travel through, but since waves must have a medium to vibrate, sound is not created where no air is present.

Explanation:

3 0

3 years ago

All electromagnetic waves

ANEK [815]

Electromagnetic Waves:

Radio waves, television waves, and microwaves.

3 0

3 years ago

One major disadvantage of breeder reactors is that they can do which of the following? Select one:a.explodeb.leak radioactivityc

zimovet [89]

definition of breeder reactors.

These are a type of nuclear reactors which produce more fissile material than they consume

Advantages: Breeder reactors produce Pu-239 which can be extensively used as a nuclear fuel. Also, Pu-239 can absorb neutron to form Pu-240, which is another fertile material.[1]

8 0

1 year ago

A(n) 55.5 g ball is dropped from a height of 53.6 cm above a spring of negligible mass. The ball compresses the spring to a maxi

Serggg [28]

Answer:

The spring force constant is $k=243\ \frac{N}{m}$ .

Explanation:

We are told the mass of the ball is $m=0.0555\ kg$ , the height above the spring where the ball is dropped is $h=0.536\ m$ , the length the ball compresses the spring is $d=0.04897\ m$ and the acceleration of gravity is $9.8\ \frac{m}{s^{2}}$ .

We will consider the initial moment to be when the ball is dropped and the final moment to be when the ball stops, compressing the spring. We supose that there is no friction so the initial mechanical energy $E_{mi}$ is equal to the final mechanical energy $E_{mf}$ :

$E_{mf}=E_{mi}$

Initially there is only gravitational potential energy because the force of the spring isn't present and the speed is zero. In the final moment there is only elastic potential energy because the height is zero and the ball has stopped. So we have that:

$\frac{1}{2}kd^{2}=mgh$