For a polynomial of the form ax^2+bx+c rewrite the middle term as a sum of two terms whose product is a⋅c=5⋅4=20 and whose sum is b=12.
<u>Factor 12 out of 12x.</u>
5x^2+12(x)+4
<u>Rewrite 12 as 2 plus 10</u>
5x^2+(2+10)x+4
Apply the distributive property.
5x^2+2x+10x+4
Factor out the greatest common factor from each group.
Group the first two terms and the last two terms.
(5x^2+2x)+10x+4
Factor out the greatest common factor (GCF) from each group.
x(5x+2)+2(5x+2)
Factor the polynomial by factoring out the greatest common factor, 5x+25x+2.
(5x+2)(x+2)
Answer:
1. 1*9^(10-1) = 387,420,489
2.2*4^(10-1) = 524,288
Step-by-step explanation:
The explicit formula for a geometric sequence is a1 * r^n-1
Where a1 is your first term, r is your ratio, and n is the amount of terms you want in the sequence
To solve for the 10th number in the sequence, we simply plug 10 in for n.
Hope this helps
Answer:
a) P=0.3174
b) P=0.4232
c) P=0.2594
d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.
Step-by-step explanation:
The appropiate distribution to model this is the hypergeometric distribution:

a) What is the probability that none of the questions are essay?

b) What is the probability that at least one is essay?

c) What is the probability that two or more are essay?
