Find the quotient of quantity of 3 times x to the 3rd power plus 9 times x to the 2nd power minus 6 times x all over negative 3

Question

4 years ago

9

times x

2 answers:

ki77a [65] · Answer 1 · 2021-12-24T17:59:27+03:00

ki77a [65]4 years ago

3 0

-x^2 -3x + 2
------------------------------
-3x ) 3x^3 + 9x^2 - 6x
3x^3
9x^2
-6x

answer is -x^2 - 3x + 2

Savatey [412] · Answer 2 · 2021-12-24T19:15:14+03:00

Answer:

Quotient = -x² -3x +2.

Step-by-step explanation:

Given : quantity of 3 times x to the 3rd power plus 9 times x to the 2nd power minus 6 times x all over negative 3 times x.

To find : Find the quotient.

Solution : We have given that statement

3 times x to the 3rd power = 3x³.

9 times x to the 2nd power =9x²

6 times x = 6x

3x³ +9x²-6x over -3x.

On dividing 3x³ +9x²-6x by -3x

$\frac{3x^{3}}{-3x} +\frac{9x^{2}}{-3x} -\frac{6x}{-3x}$ .

On cancel out the like numertor and denominator.

Quotient = -x² -3x +2

Therefore, Quotient = -x² -3x +2.