Answer:
one yard one yard is bigger. 1 yard=0.9144 meter
<span>Simplifying
(5b + -9) + -3(8 + -2b) = 0
Reorder the terms:
(-9 + 5b) + -3(8 + -2b) = 0
Remove parenthesis around (-9 + 5b)
-9 + 5b + -3(8 + -2b) = 0
-9 + 5b + (8 * -3 + -2b * -3) = 0
-9 + 5b + (-24 + 6b) = 0
Reorder the terms:
-9 + -24 + 5b + 6b = 0
Combine like terms: -9 + -24 = -33
-33 + 5b + 6b = 0
Combine like terms: 5b + 6b = 11b
-33 + 11b = 0
Solving
-33 + 11b = 0
Solving for variable 'b'.
Move all terms containing b to the left, all other terms to the right.
Add '33' to each side of the equation.
-33 + 33 + 11b = 0 + 33
Combine like terms: -33 + 33 = 0
0 + 11b = 0 + 33
11b = 0 + 33
Combine like terms: 0 + 33 = 33
11b = 33</span>
5.6mile
7 x
-- = --
80 64
7×64=80x
448=80x
x=5.6
Answer:
Option B is correct.
is equivalent to 
Step-by-step explanation:
Given expression: 
Using exponents power:
Given:
Apply exponent power :
⇒ 
⇒ 
⇒
Therefore, the expression which is equivalent to
is, 
Answer:
The least number of tennis balls needed for the sample is 1849.
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population proportion is:

The margin of error for this interval is:

Assume that the proportion of all defective tennis balls is <em>p</em> = 0.50.
The information provided is:
MOE = 0.03
Confidence level = 99%
<em>α</em> = 1%
Compute the critical value of <em>z</em> for <em>α</em> = 1% as follows:

*Use a <em>z</em>-table.
Compute the sample size required as follows:

![n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)} }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csqrt%7B%5Chat%20p%281-%5Chat%20p%29%7D%20%7D%7BMOE%7D%5D%5E%7B2%7D)
Thus, the least number of tennis balls needed for the sample is 1849.