Question

Find the quotient of quantity of 3 times x to the 3rd power plus 9 times x to the 2nd power minus 6 times x all over negative 3 times x

Answer 1

            -x^2  -3x    + 2
        ------------------------------
-3x )  3x^3 + 9x^2 - 6x
          3x^3 
                    9x^2
                             -6x

answer is -x^2 - 3x + 2

Answer 2

Answer:

Quotient = -x² -3x +2.

Step-by-step explanation:

Given :  quantity of 3 times x to the 3rd power plus 9 times x to the 2nd power minus 6 times x all over negative 3 times x.

To find : Find the quotient.

Solution : We have given that statement

3 times x to the 3rd power  = 3x³.

9 times x to the 2nd power =9x²

6 times x = 6x

3x³ +9x²-6x over -3x.

On dividing 3x³ +9x²-6x  by -3x

$\frac{3x^{3}}{-3x} +\frac{9x^{2}}{-3x} -\frac{6x}{-3x}$ .

On cancel out the like numertor and denominator.

Quotient = -x² -3x +2

Therefore, Quotient = -x² -3x +2.