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jeka57 [31]
3 years ago
7

On the moon the acceleration due to gravity is 1.6 ms if an object has a mass on earth of 5.1kg what is its mass on the moon

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
3 0

Answer:

Mass on the moon is 5.1 kg.

Explanation:

Given mass on earth = 5.1 kg

acceleration due to gravity on moon = 1.6 ms⁻².

The mass on the moon does not change because mass is the quantity of matter in the body regardless of its volume or  of any forces acting on it.

Whereas the weight of the object changed.

Weight is the the force exerted on a body which is related to mass and expressed as W = mg.

W = weight of object   m = mass of object      and g = gravitational force

So\ in\ this\ case\ W\ =1.6\times\ 5.1\ =8.16N

N stands for newton unit of weight.

Thus mass of the object on moon is same as on earth which is 5.1 kg.

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harina [27]

Given the model from the question,

  • The products are: N₂, H₂O and H₂
  • The reactants are: H₂ and NO
  • The limiting reactant is H₂
  • The balanced equation is: 3H₂ + 2NO —> N₂ + 2H₂O + H₂

<h3>Balanced equation </h3>

From the model given, we obtained the ffolowing

  • Red => Oxygen
  • Blue => Nitrogen
  • White => Hydrogen

Thus, we can write the balanced equation as follow:

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

  • Reactants: H₂ and NO
  • Product: N₂, H₂O and H₂

<h3>How to determine the limiting reactant</h3>

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

3 moles of H₂ reacted with 2 moles of NO.

Therefore,

5 moles of H₂ will react with = (5 × 2) / 3 = 3.33 moles of NO

From the calculation made above, we can see that only 3.33 moles of NO out of 4 moles given are required to react completely with 5 moles of H₂.

Thus, H₂ is the limiting reactant

Learn more about stoichiometry:

brainly.com/question/14735801

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8 0
2 years ago
How many liters of nitrogen gas are needed to make 25 mol of nitrogen trifluoride
ikadub [295]
The reaction between N₂ and F₂ gives Nitrogen trifluoride as the product. The balanced equation is;

N₂ + 3F₂ → 2NF₃

The stoichiometric ratio between N₂ and NF₃ is 1 : 2
Hence, 
  moles of N₂ / moles of F₂ = 1 / 2
  moles of N₂ / 25 mol        =  0.5
           moles of N₂            =  0.5 x 25 mol = 12.5 mol
 
Hence N₂ moles needed  = 12.5 mol

At STP (273 K and 1 atm) 1 mol of gas = 22.4 L

Hence needed N₂ volume = 22.4 L mol⁻¹ x 12.5 mol
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Answer:

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