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Len [333]
3 years ago
14

Determine the energy of a photon whose frequency is 1.59x10^17 Hz.

Chemistry
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

The answer is

1.05 \times  {10}^{ - 16}  \:  \:  \: J

Explanation:

To find the energy of the photon we use the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 1.59x10^17 Hz

We have

E = 1.59 \times  {10}^{15}  \times 6.626 \times  {10}^{ - 34}  \\

We have the final answer as

1.05 \times  {10}^{ - 16}  \:  \:  \: J

Hope this helps you

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8 0
3 years ago
A binary compound created by reaction of bismuth and an unknown element E contains 52.07% Bi and 47.93% E by mass. If the formul
yulyashka [42]

Answer:

Atomic mass of E is 128.24

Explanation:

  • The percentage composition by mass of an element in a compound is given by dividing the mass of the element by the total mass of the compound and expressing it as a percentage.
  • In this case; the compound Bi₂E₃

Percentage composition of bismuth = 52.07%

Percentage composition of E = 47.93%

Mass Bismuth in the compound is (2×208.9804) = 417.96 g

Therefore,

To calculate the atomic mass of E

52.07% = 417.96 g

47.93% = ?

            = (47.93 × 417.96 ) ÷ 52.07 %

            = 384.729

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                     = 128.24  

The atomic mass of E is 128.24

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