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Len [333]
3 years ago
14

Determine the energy of a photon whose frequency is 1.59x10^17 Hz.

Chemistry
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

The answer is

1.05 \times  {10}^{ - 16}  \:  \:  \: J

Explanation:

To find the energy of the photon we use the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 1.59x10^17 Hz

We have

E = 1.59 \times  {10}^{15}  \times 6.626 \times  {10}^{ - 34}  \\

We have the final answer as

1.05 \times  {10}^{ - 16}  \:  \:  \: J

Hope this helps you

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To calculate this, we will use the following formulas:
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So, we know:
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We need:
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We could first use the second equation to calculate n:
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<span>(1/2)^{n} = x
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