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Len [333]
4 years ago
14

Determine the energy of a photon whose frequency is 1.59x10^17 Hz.

Chemistry
1 answer:
PIT_PIT [208]4 years ago
4 0

Answer:

The answer is

1.05 \times  {10}^{ - 16}  \:  \:  \: J

Explanation:

To find the energy of the photon we use the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 1.59x10^17 Hz

We have

E = 1.59 \times  {10}^{15}  \times 6.626 \times  {10}^{ - 34}  \\

We have the final answer as

1.05 \times  {10}^{ - 16}  \:  \:  \: J

Hope this helps you

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(a) Power of bulb is 100 W, converting this into kW.

1 W=\frac{1}{1000}kW

Thus,

100 W =\frac{100}{1000}kW=0.1 kW

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t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.1 kW\times 2190 h=219 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 219 kW.h will be:

Cost=\$ (219\times 0.15)=\$ 32.85

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(b) Power of bulb is 25 W, converting this into kW.

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Thus,

100 W =\frac{25}{1000}kW=0.025 kW

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t=6\times 365=2190 h

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E=P\times t=0.025 kW\times 2190 h=54.75 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 54.75 kW.h will be:

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