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Len [333]
3 years ago
14

Determine the energy of a photon whose frequency is 1.59x10^17 Hz.

Chemistry
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

The answer is

1.05 \times  {10}^{ - 16}  \:  \:  \: J

Explanation:

To find the energy of the photon we use the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 1.59x10^17 Hz

We have

E = 1.59 \times  {10}^{15}  \times 6.626 \times  {10}^{ - 34}  \\

We have the final answer as

1.05 \times  {10}^{ - 16}  \:  \:  \: J

Hope this helps you

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Sulfur burns in the air to form 33.6L of sulfur dioxide. (S = 32, O =16, 64g of sulfur dioxide has 22.4L, 32g of oxygen has 22.4
ivolga24 [154]

The mass of oxygen reacted/required in this reaction is obtained as 48g.

<h3>What is stoichiometry?</h3>

The term stoichiometry has to do with mass- volume or mass - mole relationship which ultimately depends on the balanced reaction equation.

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If 1 mole of sulfur dioxide contains 22.4 L

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Since the reaction is 1:1, the number if moles of oxygen required/reacted is 1.5 moles.

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2 years ago
A 15.00 % by mass solution of lactose (C 12H 22O 11, 342.30 g/mol) in water has a density of 1.0602 g/mL at 20°C. What is the mo
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Answer:

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A gas at constant volume has a pressure of 3.20 atm at 300. K. What will be the pressure of the gas at 290. K?
melomori [17]
  • From the general law of gases: PV = nRT,

where P is the pressure (atm),

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n is the number of moles,

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T is the temperature in Kelvin

  • at constant volume of the gas: P1T2 = P2T1

P1 = 3.20 atm, T1 = 300 K, T2 = 290 K, P2 = ??

(3.20 atm)(290 K) = P2(300 K)

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