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shtirl [24]
2 years ago
8

Part H)

Physics
1 answer:
kykrilka [37]2 years ago
5 0

At t = 0 a truck starts from rest at x = 0 and speeds up in the positive x-direction on..., the time the truck passes the car and the coordinate the truck passes the car is mathematically given as

  • t = \frac{2v_{C}}{a_{T} + a_{C}}
  • d_{T} = v_{T}t + \frac{a_{T}t^{2}}{2}
<h3>What time does the truck pass the car and coordinate does the truck pass the car?</h3>

Generally, the equation for Distance traveled is mathematically given as

By Truck

d_{T} = v_{T}t + \frac{a_{T}t^{2}}{2}

By Car

d_{C} = v_{C}t - \frac{a_{C}t^{2}}{2}

In conclusion, when the conditions the truck passes the car

d_{T} = d_{C}

Therefore

v_{t} + \frac{a_{t}t}{2} = v_{C} - \frac{a_{C}t}{2}

\frac{a_{T}t}{2} = v_{C} - \frac{a_{C}t}{2}

Therefore

t = \frac{2v_{C}}{a_{T} + a_{C}}

differentiation of  T

d_{T} = v_{T}t + \frac{a_{T}t^{2}}{2}

Read more about Speed

brainly.com/question/4931057

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