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Aliun [14]
3 years ago
15

1.5kj of energy are used every second by a microwave oven, what is the power rating of the oven?

Physics
2 answers:
Dennis_Churaev [7]3 years ago
7 0

Power is the rate at which energy is consumed. When 1 J of energy is consumed in one second, the power consumed is 1 watt.

The microwave consumes 1.5 kJ of energy.

In joules, the energy consumed is 1500 J

P=\frac{E}{t}

Here, E is the energy consumed in time interval <em>t.</em>

The power rating of the microwave is therefore,

P=\frac{1500J}{1 s} \\ =1500 W

Thus, the power rating of the oven is 1500 W or 1.5 kW

Artemon [7]3 years ago
7 0
Power = work/ time
Power = 1.5 kj/ 1s
Power = 1.5kW
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r is the distance measured from the centre of the planet.

In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
r=R+h=6370 km+300 km=6670 km= 6.67 \cdot 10^{6} m

And now we can use the previous equation to calculate the field strength at that altitude:
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<h3>Angular velocity of the tire</h3>

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

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<h3>Tangential velocity of the tire</h3>

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.

The magnitude of the tangential velocity is caculated as follows;

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Learn more about tangential velocity here: brainly.com/question/25780931

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