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Aliun [14]
3 years ago
15

1.5kj of energy are used every second by a microwave oven, what is the power rating of the oven?

Physics
2 answers:
Dennis_Churaev [7]3 years ago
7 0

Power is the rate at which energy is consumed. When 1 J of energy is consumed in one second, the power consumed is 1 watt.

The microwave consumes 1.5 kJ of energy.

In joules, the energy consumed is 1500 J

P=\frac{E}{t}

Here, E is the energy consumed in time interval <em>t.</em>

The power rating of the microwave is therefore,

P=\frac{1500J}{1 s} \\ =1500 W

Thus, the power rating of the oven is 1500 W or 1.5 kW

Artemon [7]3 years ago
7 0
Power = work/ time
Power = 1.5 kj/ 1s
Power = 1.5kW
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<h3><u>Answers;</u></h3>

Antarctica and Greenland

Present day glaciers are found primarily in <em><u>Antarctica and Greenland</u></em>.

<h3><u>Explanation;</u></h3>
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3 years ago
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An athlete jumping vertically on a trampoline leaves the surface with a velocity of 8.5 m/s upward. what maximum height does she
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3 years ago
What is 18 m/s north an example of?
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Answer:

It is an example of velocity

Explanation:

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7 0
3 years ago
Car A starts in Sacramento at 11am. It travels along 400 mile route to Los Angeles at 60 mph. Car B starts from Los Angeles at n
damaskus [11]

Answer:

  • 38.89 miles

Explanation:

from the question we have the following:

distance between Sacramento and los angles = 400 miles

speed of car A = 60 mph

start time of car A = 11 am

speed of car B = 75 mph

start time of car B = 12 pm

distance of Fresno from Los Angeles = 150 miles

  • To start off let's allow car A to travel for one hour (from 11 am to 12 pm), during which it would have covered a distance of 60 miles.
  • Now the time would be 12 pm and the distance between the two cars would be 400 - 60 (distance traveled by car A within 11 am to 12 pm) = 340 miles
  • From 12 pm to the time both cars will meet, the distance covered by car A + distance covered by car B would be equal to 340 miles. Therefore
  • Distance covered by car A = speed x time(t) = 60 x t = 60t
  • Distance covered by car B = speed x time(t) = 75 x t = 75t
  • 60t + 75t = 340 miles
  • 135t = 340
  • t = 2.51 hours
  • Recall that at their meeting point, the distance covered by car B = 75t = 75 x 2.62 = 188.89 miles
  • Since Fresno is 150 miles from Los Angeles, car B which is 188.89 miles from Los Angeles at their meeting point would be 188.89 - 150 = 38.89 miles from Fresno
  • 38.89 miles would also be the distance of car A from Fresno since that is their meeting point.

4 0
3 years ago
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