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sasho [114]
4 years ago
15

A vehicle of 1 200 kg is moving at a speed of 40 km/h on an incline of 1 in 50. The total constant rolling and wind resistance i

s 600 N. The efficiency of the drive from the engine trough the gearbox to the wheels is 80 % and the gear ratio causes a final engine to wheel velocity ratio of 4:1. The effective wheel diameter is 500 mm. Calculate the engine power to maintain this speed.
Engineering
1 answer:
Readme [11.4K]4 years ago
4 0

Answer:11.602 KW

Explanation:

mass of vehicle\left ( m\right )=1200 kg

speed=40Km/h

Resistance=600 N

\eta =80%

Gear ratio\left ( G\right )=4:1

D_{effective}=500mm

Net force to overcome by engine is

F=Resistance + sin component of weight

F=600+mgsin\theta

Where tan\theta =[tex]\frac{1}{50}

\theta =1.1457^{\circ}

F=600+1200\times 9.81\times sin\left ( 1.1457\right )

F=600+235.38=835.38 N

power=F.v=835.38\frac{100}{9}

Engine Power=\frac{835.\frac{100}{9}}{\eta }=11.602 KW

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