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sertanlavr [38]

3 years ago

13

Lars is a medical coder. He works for a hospital in Wisconsin but currently lives in Georgia. Lars does his work online and over

conference calls. Lars is an example of a remote worker.
True or False

1 answer:

Brums [2.3K]3 years ago

6 0

The answer is True because he works in one location while on another

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There are two types of cellular phones, handheld phones (H) that you carry and mobile phones (M) that are mounted in vehicles. P

nexus9112 [7]

Answer:

A) P(W) = 0.5

B) P(MF) = 0.3

C) P(H) = 0.6

Explanation:

We are told that there are two types of cellular phones which are handheld phones (H) that you carry and mobile phones (M) that are mounted in vehicles.

Also, Phone calls can be classified by the traveling speed of the user as fast (F) or slow (W).

Thus, the sample space is combination of types and classification we are given and it is written as;

S = {HF, HW, MF, MW}

A) Now, phones can either be fast(F) or slow(W). Thus, we can write;

P(F) + P(W) = 1

We are given P(F) = 0.5

Thus;

0.5 + P(W) = 1

P(W) = 1 - 0.5

P(W) = 0.5

B) Now, from the problem statement, a phone call can either be made with a handheld(H) or mobile(M). Thus the sample space partition is {H, M} and we can express as;

P(H ∩ F) + P(M ∩ F) = P(F)

We are given P[F] = 0.5 and P[HF] = 0.2.

P(H ∩ F) is same as P[HF]

Also, P(M ∩ F) is same as P(MF)

Thus;

0.2 + P(MF) = 0.5

P(MF) = 0.5 - 0.2

P(MF) = 0.3

C) Similarly, mobile Phone calls can either be fast or slow. It means the sample space partition is {F, W}

Thus;

P(M) = P(MW) + P(MF)

P(M) = 0.1 + 0.3

P(M) = 0.4

Now, since cellular phones can either be handheld(H) or Mobile(M), then we can say;

P(H) + P(M) = 1

P(H) + 0.4 = 1

P(H) = 1 - 0.4

P(H) = 0.6

5 0

3 years ago

The modulus of elasticity for a ceramic material having 6.0 vol% porosity is 303 GPa. (a) Calculate the modulus of elasticity (i

Phantasy [73]

Answer:

modulus of elasticity for the nonporous material is 340.74 GPa

Explanation:

given data

porosity = 303 GPa

modulus of elasticity = 6.0

solution

we get here modulus of elasticity for the nonporous material Eo that is

E = Eo (1 - 1.9P + 0.9P²) ...............1

put here value and we get Eo

303 = Eo ( 1 - 1.9(0.06) + 0.9(0.06)² )

solve it we get

Eo = 340.74 GPa

8 0

3 years ago

The 10-lb block is pressed against the spring so as to compress it 2 ft when it is at a point A. If the plane is smooth, determi

leva [86]

Answer:

The distance measure from the wall = 36ft

Explanation:

Given Data:

w = 10

g =32.2ft/s²

x = 2

Using the principle of work and energy,

T₁ +∑U₁-₂ = T₂

0 + 1/2kx² -wh = 1/2 w/g V²

Substituting, we have

0 + 1/2 * 100 * 2² - (10 * 3) = 1/2 * (10/32.2)V²

170 = 0.15528V²

V² = 170/0.15528

V² = 1094.796

V = √1094.796

V = 33.09 ft/s

But tan ∅ = 3/4

∅ = tan⁻¹3/4

= 36.87°

From uniform acceleration,

S = S₀ + ut + 1/2gt²

It can be written as

S = S₀ + Vsin∅*t + 1/2gt²

Substituting, we have

0 = 3 + 33.09 * sin 36.87 * t -(1/2 * 32.2 *t²)

19.85t - 16.1t² + 3 = 0

16.1t² - 19.85t - 3 = 0

Solving it quadratically, we obtain t = 1.36s

The distance measure from the wall is given by the formula

d = VCos∅*t

Substituting, we have

d = 33.09 * cos 36. 87 * 1.36

d = 36ft

5 0

3 years ago

Read 2 more answers

The largest class of errors in software engineering can be attributed to _______.

Ilya [14]

Answer:

improper imput validation

Explanation:

6 0

2 years ago

Describe the cartesain coordinate system.

olga nikolaevna [1]

Answer:

Cartesian coordinate system is used to specify any point on a plane.

In two dimensional plane,the two types of axes or coordinates are $x$ and $y$ axis.

Explanation:

Cartesian coordinate system specifies each point and every point on axes.

A Cartesian Coordinate system in two dimension also named as rectangular coordinate system.

The two types of axes or coordinates are $x$ and $y$ axis.

The horizontal axis is $x$ -axis and vertical axis is named as $y$ -axis.

The coordinate system specifies each point as a set of numerical coordinates in a plane which are signed from negative to positive. that is from ( $-\infty$ , $\infty$ ).

In three dimensional plane, $x$ , $y$ and $z$ coordinates are used and in two dimensional plane, $x$ and $y$ coordinates are used to address any point in the interval ( $-\infty$ , $\infty$ ).

For defining both the coordinates, the two perpendicular directed lines $x$ - axis and $x$ -axis are drawn.

Now, for example $(3,4)$ is a point in which indicates that the value of $x$ is $3$ and $y$ is $4$ .

It is drawn by moving $3$ units right from the origin to positive $x$ axis and $4$ units upwards from the origin $(0,0)$ to positive $y$ -axis.

5 0

3 years ago