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Ilya [14]
3 years ago
8

A steel cylindrical pressure vessel has an inside diameter of 2m and a wall thickness of 2cm. If the steel has a yield stress Y

= 425 MPa, calculate the tank pressure that would just cause yielding of the tank material:
Engineering
1 answer:
Feliz [49]3 years ago
4 0

Answer:

The pressure that will cause yielding in the tank in the longitudinal direction is 1.7 Mpa

Explanation:

We are dealing with a thin-walled pressure vessel here.

the formula for calculating the hoops stress of this pressure vessel is \sigma =P d/4t

\sigma Y = longitudinal yield stress = 425  \times 10^{6} Pa

Thickness = 2/1000 =0.002m

Outside diameter = inside siameter + thickness =  2m + 0.002m= 2.002m

Dm = Mean diameter = Outside diameter - thickness = 2.002 - 0.002 = 2m

P= 425 \times 10^{6} \times 4 \times 0.002 /2=1.7 Mpa

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