Answer:
1.6605 × 10⁻²³ g / atom , 9.99 amu
Explanation:
Atoms present in 1 mole = 6.022 × 10²³ atoms
Given that
Moles of common Eastern mole = 8.3 moles
So,
Atoms in 8.3 moles are:
8.3 moles = 6.022 × 10²³ × 8.3 atoms
Also,
Average mass = Mass of the sample / Number of atoms
Mass of sample = 83 g
Average mass = 83 g / 6.022 × 10²³ × 8.3 atoms = 1.6605 × 10⁻²³ g / atom
In amu :
1 amu = 1.66 × 10⁻²⁴ g / atom
So,
Average mass = 1.6605 × 10⁻²³ / 1.66 × 10⁻²⁴ amu = 9.99 amu
Answer:
F has the smallest atomic radius.
Explanation:
Atomic radius is one of the perIodic properties defined by the Periodic Table.
Atomich radius is the distance to the nucleus that comprises 95 % of the density electronic load. It can be defined as a function of the internuclear distance. Although this distance varies, depending on whether the atoms are linked by a chemical bond or simply in contact without forming link.
Atomic radius is a periodic property that increases by period (from the top to below) and decreases (from left to right) by group.
In the same group are O and F, so F < O
In the same group, we have S and Cl, so Cl < S
As Cl and F are in the same period, we define the atomic radius Cl > F and
S > Cl (In the same period)
The right way to order the elements are S > Cl > O > F
Would be considered as an iconic bond.
PE= weight x height. (remember weight is the force of gravity acting on objects...NOT the same as mass)
PE=3*2*9.8
PE=6*9.8
PE=58.8 J (for joules which is the unit for both Kinetic and potential energy)
Hope this helps :D
Explanation:
where's the question, please?