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kaheart [24]
4 years ago
6

What concentration of NO−3NO3− results when 897 mL897 mL of 0.497 M NaNO30.497 M NaNO3 is mixed with 813 mL813 mL of 0.341 M Ca(

NO3)2?
Chemistry
1 answer:
ZanzabumX [31]4 years ago
8 0

Answer:

Explanation:

NaNO₃  = Na⁺  + NO₃⁻¹

.497 M                 .497 M

moles of NO₃⁻¹ = .897 x .497 = .4458 moles

Ca( NO₃)₂  = Ca + 2 NO₃⁻¹

.341 M                    2 x .341 M = .682 M

moles of NO₃⁻¹ = .813 x .682 = .5544 moles

Total moles =  .4458 moles  +  .5544 moles

= 1.0002 moles

volume of solution = 897 + 813 = 1710 mL

= 1.710 L

concentration of nitrate ion = 1.0002 / 1.710 M

= .585 M

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3 0
3 years ago
Use LeChâtelier's principle explain why the concentration of NO at equilibrium increases when the reacuon takes place at higher
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increasing the temperature shifts the equilibrium in the direction of the reaction in which heat is absorbed.

Explanation:

The concentration of NO at equilibrium will increase when the reaction takes place at a higher temperature because increasing the temperature shifts the equilibrium in the direction of the reaction in which heat is absorbed.

The reaction is an endothermic reaction.

                            N₂  + O₂  + heat  ⇄  2NO

According to Le Chatelier's principle, "if any of the conditions of a system in equilibrium is changed the system will adjust itself in order to annul the effect of the change".

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learn more:

Thermodynamics of reactions brainly.com/question/10567109

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