Answer:
a) ∆T=T1-T2
b) At the particle level the temperature changes are the result of the added energy causing the particles of water to move more vigorously. Either the particles of solid vibrate more vigorously about their fixed positions or the particles of liquid and gas move about their container more rapidly.
c) The state in which two substances in physical contact do not share any heat energy. The temperature of two substances in thermal equilibrium is said to be the same. Also see thermodynamics.
Explanation:
hope that helped good luck!
Answer:
4 moles of SO3 will be produced from 6 moles of oxygen.
Explanation:
From the reaction given
S8 + 12 O2 ----> 8 SO3
12 moles of oxygen reacts to form 8 moles of SO3
if 6 moles of oxygen were to be used instead, it has been reduced to half of the original mole of oxygen used. Then the moles of SO3 will also be reduced to half.
6 moles of O2 will yield 4 moles of SO3
12 moles = 8 moles
6 moles = ?
? = 6 * 8 / 12
? = 48/ 12
? = 4 moles of SO3.
The traditional method is to heat the compound in an oven, on a hot plate or over a Bunsen burner. Waters of hydration are loosely bound in the compound and can be driven off at temperatures below the melting point of the compound. So the answer is heating.
Answer:

Explanation:
Hello!
In this case, since the mole fraction of both gases in the tank is computed via:

It means we need to compute the moles of each gas, just as it is shown down below:

Thus, the mole fractions turn out:

Best regards!
Answer:
Conversion of kinetic energy to potential energy (chemo mechanical energy)
In the state of rest, the rubber is a tangled mass of long chained cross-linked polymer that due to their disorderliness are in a state of increased entropy. By pulling on the polymer, the applied kinetic energy stretches the polymer into straight chains, giving them order and reducing their entropy. The stretched rubber then has energy stored in the form of chemo mechanical energy which is a form of potential energy
Conversion of the stored potential energy in the stretched to kinetic energy
By remaining in a stretched condition, the rubber is in a state of high potential energy, when the force holding the rubber in place is removed, due to the laws of thermodynamics, the polymers in the rubber curls back to their state of "random" tangled mass releasing the stored potential energy in the process and doing work such as moving items placed in the rubber's path of motion such as an object that has weight, w then takes up the kinetic energy 1/2×m×v² which can can result in the flight of the object.
Explanation: