3 years ago

Pls help me!!! I'm timed

1 answer:

3 0

The domain is the x-axis and the range is the y-axis.

So the range of the function would be the Y values given.

So the range would be (3, 6, 9, 12, 15).

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yuradex [85]

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3 years ago

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2 years ago

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Can somebody explain this to me when 2du = 16xdx ???

tamaranim1 [39]

When you set $u=4x^2+4$ , you end up with the differentials $\mathrm du=8x\,\mathrm dx$ . Multiplying both sides by 2 gives $2\,\mathrm du=16x\,\mathrm dx$ .

Then the integral is

$\displaystyle\int_0^1\frac{16x}{(4x^2+4)^2}\,\mathrm dx=\int_4^8\frac2{u^2}\,\mathrm du=-\frac2u\bigg|_{u=4}^{u=8}=-2\left(\frac18-\frac14\right)=\frac14$