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Svetlanka [38]
3 years ago
14

Onsider a galvanic cell in which al3 is reduced to elemental aluminum, and magnesium metal is oxidized to mg2 . write the balanc

ed half-cell reactions that take place at the cathode and at the anode.
Chemistry
2 answers:
jok3333 [9.3K]3 years ago
8 0
Two Half Cell reactions are as follow,

                                    3e⁻  +    Al⁺³    →  Al            (Reduction Reaction)

                                    Mg   →   Mg⁺²  +  2e⁻           (Oxidation Reaction)

In order to balance the number of electrons, multiply reduction reaction by 2 and oxidation reaction by 3.
So,
                                    6e⁻  +    2 Al⁺³    →  2 Al           

                                    3 Mg   →   3 Mg⁺²  +  6e⁻           (e⁻ cancelled)
                                _______________________

                               2 Al⁺³ + 3 Mg  →  2 Al  +  3 Mg⁺²

Result:
            At Anode
Magnesium metal is Oxidized and At Cathode Aluminium Ions are reduced.
zalisa [80]3 years ago
5 0

The balanced reduction half-cell reaction at cathode is \boxed{{\text{A}}{{\text{l}}^{3+}}+3{e^-}\to{\text{Al}}}  

The balanced oxidation half-cell reaction at anode is \boxed{{\text{Mg}}\to{\text{M}}{{\text{g}}^{2+}}+2{e^-}}  

Further Explanation:

Redox reaction:

Redox is a term that is used collectively for the reduction-oxidation reaction. It is a type of chemical reaction in which the oxidation states of atoms are changed. In this reaction, both reduction and oxidation are carried out simultaneously. Such reactions are characterized by the transfer of electrons between the species involved in the reaction.

The process of <em>gain of electrons</em> or the decrease in the oxidation state of the atom is called <em>reduction </em>while that of <em>loss of electrons</em> or the increase in the oxidation number is known as <em>oxidation</em>. In redox reactions, one species lose electrons and the other species gain electrons. The species that lose electrons and itself gets oxidized is called as a reductant or reducing agent. The species that gains electrons and gets reduced is known as an oxidant or oxidizing agent. The presence of a redox pair or redox couple is a must for the redox reaction.

The general representation of a redox reaction is,

{\text{X}}+{\text{Y}}\to{{\text{X}}^+}+{{\text{Y}}^-}

The oxidation half-reaction can be written as:

{\text{X}}\to{{\text{X}}^+}+{e^-}

The reduction half-reaction can be written as:

{\text{Y}}+{e^-}\to{{\text{Y}}^-}

Here, X is getting oxidized and its oxidation state changes from 0 to +1 whereas B is getting reduced and its oxidation state changes from 0 to -1. Hence, X acts as the reducing agent whereas Y is an oxidizing agent.

Reduction occurs at cathode whereas oxidation takes place at anode. So {\text{A}}{{\text{l}}^{3+}}  is reduced to form Al at cathode and Mg is oxidized to {\text{M}}{{\text{g}}^{2+}}  at anode.

The balanced reduction half-cell reaction at cathode is,

{\text{A}}{{\text{l}}^{3+}}+3{e^-}\to{\text{Al}}

The balanced oxidation half-cell reaction at anode is,

{\text{Mg}}\to{\text{M}}{{\text{g}}^{2+}}+2{e^-}

Learn more:

1. Which occur during redox reaction? <u>brainly.com/question/1616320</u>

2. Oxidation and reduction reaction: <u>brainly.com/question/2973661</u>

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Redox reactions

Keywords: redox reaction, Mg, Mg2+, Al, Al3+, 2e-, 3e-, cathode, anode, half-cell reaction, oxidation, reduction, reductant, oxidant, reducing agent, oxidizing agent, electrons, redox pair, redox couple, oxidation state, oxidized, reduced, simultaneously, increase, decrease.

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Answer:

3.11 is the pH of the buffer

Explanation:

The pH of a buffer is obtained using H-H equation:

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<em>Where pH is the pH of the buffer, pKa = -log Ka = 3.14 for the citric buffer and [] could be taken as the moles of each species.</em>

The citric acid,HX (Weak acid), reacts with NaOH to produce sodium citrate, NaX (weak base) and water:

HX + NaOH → H2O + NaX

That means the moles of NaOH added = Moles of sodium citrate produced

And the resulitng moles of HX = Initial moles - Moles NaOH added

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Moles NaOH = 0.100L * (0.65mol / L) = 0.065 moles NaOH = Moles NaX

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8 0
3 years ago
If calcium carbonate (caco3) decomposes, what would the product of the reaction be? caco3 → co2
pychu [463]

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CaCO₃ is calcium carbonate.

CaO is calcium oxide

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2 years ago
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mihalych1998 [28]

Answer:

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Explanation:

7 0
4 years ago
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Consider the reaction data.
Snowcat [4.5K]

Answer:

(a) x₁= 0.004 444; (b) y₁ = -0.9545; (c) x₂ = 0.001 905; (d) y₂ = -0.4541;

(e) rise = 0.5004; (f) run = -0.002 539; (g) slope = -197.1; (h) Eₐ = -1.64 kJ·mol⁻¹

Explanation:

This is an example of the Arrhenius equation:

k = Ae^{-E_{a}/RT}\\\text{Take the ln of each side}\\\ln k = \ln A - \dfrac{E_{a}}{RT}\\\\\text{We can rearrange this to give}\\\ln k = -\left ( \dfrac{E_{a}}{R} \right )\dfrac{1}{T} + \ln A

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(a) x₁

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(b) y₁

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(c) x₂

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(d) y₂

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(f) Run

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(g) Slope

Δy/Δx = 0.5004/(-0.002 539) K⁻¹ = -197.1

(h) Activation energy

Slope = -Eₐ/R

Eₐ = -R × slope = -8.314 J·K⁻¹mol⁻¹ × (-197.1 K⁻¹) = 1638 J/mol = 1.64 kJ/mol

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