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IrinaVladis [17]
3 years ago
15

We can also use the equation for enthalpy change for physical phase changes. Consider the phase change H2O(l) → H2O(g). Calculat

e ΔHrxn.
Use ΔHf values from the table above.

ΔHrxn = _____
Chemistry
2 answers:
DIA [1.3K]3 years ago
7 0
Standard molar enthalpy:
H2O ( liquid water ) : - 285.8 KJ/mole
H2O ( water vapor ) : - 241.8 KJ / mole.
ΔHrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0
Answer: B ) 44.0 KJ  
VLD [36.1K]3 years ago
6 0

Answer: The value of enthalpy of the given reaction is 44.000 kJ/mol , that is energy is supplied to water to change into water vapors

Explanation:

H_2O(l)\rightarrow H_2O(g),\Delta H_{rxn}=?

Enthalpy of formation of water in liquid state,\Delta H_{f,H_2O(l)}=-285.820 kJ/mol

Enthalpy of formation of water in gaseous state,\Delta H_{f,H_2O(g)}=-241.820 kJ/mol

\Delta H_{rxn}=\sum \Delta H_f \text{of products}-\sum \Delta H_f \text{of reactants}

\Delta H_{rxn}=(-241.820 kJ/mol)-(-285.820 kJ/mol)=44.000 kJ/mol

The value of enthalpy of the given reaction is 44.000 kJ/mol, that is energy is supplied to water to change into water vapors.

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