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3 years ago

Deserts are increasing world wide. This is known as

Chemistry

1 answer:

Leya [2.2K]3 years ago

7 0

The answer is B.Desertification

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Even though lead is toxic, lead compounds were used in ancient times as white pigments in cosmetics. What is the percentage of l

Gekata [30.6K]

Answer: The mass percent of lead in lead (IV) carbonate is 63.32 %

Explanation:

The given chemical formula of lead (IV) carbonate is $Pb(CO_3)_2$

To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:

$\text{Mass percent of lead}=\frac{\text{Mass of lead}}{\text{Mass of lead (IV) carbonate}}\times 100$

Mass of lead = (1 × 207.2) = 207.2 g

Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g

Putting values in above equation, we get:

$\text{Mass percent of lead}=\frac{207.2g}{327.2g}\times 0100=63.32\%$

Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %

4 0

3 years ago

I NEED THIS NOW AND NO LINKS OR ILL REPORT

kolbaska11 [484]

Aluminum or glass I think

3 0

2 years ago

Read 2 more answers

What number of moles of Pb (NO3)2 is consumed when 54 g of KNO3 is produced

Ivenika [448]

Explanation:

hope it helps you understand moles

5 0

3 years ago

Is bleach liquid starch? Yes or No

Jobisdone [24]

Answer:

O it's not

Explanation:

Have a great day!

8 0

2 years ago

600 s after initiation of a first order reaction 48.5% of the initial reactant concentration remains present. What is the rate c

Ludmilka [50]

Answer:

$k=1.20x10^{-3} s^{-1}$

Explanation:

For a first order reaction the rate law is:

$v=\frac{-d[A]}{[A]}=k[A]$

Integranting both sides of the equation we get:

$\int\limits^a_b {\frac{d[A]}{[A]}} \, dx =-k\int\limits^t_0 {} \, dt$

where "a" stands for [A] (molar concentration of a given reagent) and "b" is {A]0 (initial molar concentration of a given reagent), "t" is the time in seconds.

From that integral we get the integrated rate law:

$ln\frac{[A]}{[A]_{0} } =-kt$

$[A]=[A]_{0}e^{-kt}$

$ln[A]=ln[A]_{0} -kt$

$k=\frac{ln[A]_{0}-ln[A]}{t}$

therefore k is

$k=\frac{ln1-ln0,485}{600}=1,20x10^{-3}$

8 0

3 years ago