Deserts are increasing world wide. This is known as

H2S what species are present at 10-6 mol/L or greater when dissolved in water

Anastaziya [24]

Answer:

the answer has been given below have a good day

Explanation:

mark as brainiest

5 0

3 years ago

The reducing agent in a material is the one that A. gains electrons. B. increases its atomic number. C. is reduced. D. is oxidiz

Bas_tet [7]

D. Is Oxidized Hope I helped.

4 0

3 years ago

Read 2 more answers

0.0027432 using scientific notation

alexira [117]

Answer: 2.7423 × 10^-3

Explanation:

4 0

3 years ago

Human blood has a pH between 7.35 and 7.45. Which of the following best describes human blood?

uysha [10]

Answer:

C. slightly basic

Explanation:

0-7 = acidic

7 = neutral

7-14 = basic

- Since the pH is just over 7, the answer would be slightly basic.

- Hope this helps! Please let me know if you need a further explanation.

6 0

3 years ago

Nitric oxide (NO) reacts readily with chlorine gas as follows.2 NO(g) + Cl2(g) equilibrium reaction arrow 2 NOCl(g)At 700. K the

Yanka [14]

Answer:

For a: The mixture will need to produce more reactants to reach equilibrium.

For b: The mixture will need to produce more reactants to reach equilibrium.

For c: The mixture will need to produce more products to reach equilibrium.

Explanation:

For the given chemical equation:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

The expression of $K_{p}$ for above equation follows:

$K_{p}=\frac{(p_{NOCl})^2}{(p_{NO})^2\times p_{Cl_2}}$ .....(1)

We are given:

Value of $K_p$ = 0.26

There are 3 conditions:

When $K_{p}>Q_p$ ; the reaction is product favored.
When $K_{p}$ ; the reaction is reactant favored.
When $K_{p}=Q_p$ ; the reaction is in equilibrium.

For the given options:

For a:

We are given:

$p_{NOCl}=0.11atm\\p_{NO}=0.16atm\\p_{Cl_2}=0.30atm$

Putting values in expression 1, we get:

$Q_p=\frac{(0.11)^2}{(0.16)^2\times 0.30}=1.57$

As, $K_{p}$ ; the reaction is reactant favored

Hence, the mixture will need to produce more reactants to reach equilibrium.

For b:

We are given:

$p_{NOCl}=0.048atm\\p_{NO}=0.12atm\\p_{Cl_2}=0.10atm$

Putting values in expression 1, we get:

$Q_p=\frac{(0.048)^2}{(0.12)^2\times 0.10}=1.6$

As, $K_{p}$ ; the reaction is reactant favored

Hence, the mixture will need to produce more reactants to reach equilibrium.

For c:

We are given:

$p_{NOCl}=5.20\times 10^{-3}atm\\p_{NO}=0.15atm\\p_{Cl_2}=0.15atm$

Putting values in expression 1, we get:

$Q_p=\frac{(5.20\times 10^{-3})^2}{(0.15)^2\times 0.15}=0.008$

As, $K_{p}>Q_p$ ; the reaction is product favored.

Hence, the mixture will need to produce more products to reach equilibrium.

8 0

3 years ago