Answer:
is the solubility of nitrogen gas in a diver's blood.
Explanation:
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
To calculate the molar solubility, we use the equation given by Henry's law, which is:

where,
= Henry's constant = 
= partial pressure of nitrogen
(Raoult's law)



is the solubility of nitrogen gas in a diver's blood.
The contraction of the triceps muscle causes the arm to flex. The contraction of the triceps muscle causes the arm to extend. When added to the force of the biceps contracting it provides extra force to the ball.
The answer is A
Answer:


Explanation:
Hola.
En este caso, para calcular la longitud (a) de una cara de celda unitaria, consideramos la siguiente ecuación:

En la que consideramos el número de átomos por celda (4 para FCC), la masa molar (40.3 g/mol para MgO) y el número de avogadro para obtener:

Despejando para a, obtenemos:
![a^3 = \frac{4atom/celda*40.3g/mol}{3.581g/cm^3*6.02x10^{23}atom/mol}\\\\a=\sqrt[3]{7.478cm^3} \\\\a=4.213cm](https://tex.z-dn.net/?f=a%5E3%20%3D%20%5Cfrac%7B4atom%2Fcelda%2A40.3g%2Fmol%7D%7B3.581g%2Fcm%5E3%2A6.02x10%5E%7B23%7Datom%2Fmol%7D%5C%5C%5C%5Ca%3D%5Csqrt%5B3%5D%7B7.478cm%5E3%7D%20%5C%5C%5C%5Ca%3D4.213cm)
Finalmente, el radio lo calculamos como:

¡Saludos!
<span>Hydrogen fusion generates the energy for proton - proton chains and the carbon nitrogen oxygen cycle. It is the nuclear fusion of 4 protons to form a helium 4 nucleus.</span>