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Stels [109]
3 years ago
10

Pastries made out of filo dough are brushed with either olive oil or butter (but not both). Pastries made out of shortcrust doug

h are not brushed with anything.
Rashid and Mikhail submitted a total of x pastries to a baking competition. Mikhail used filo dough for all of his pastries, Rashid used shortcrust dough for all of his pastries, and each pastry was made using only one kind of dough.

If Rashid made 2/3 as many pastries as Mikhail, and 5/8 of the filo dough pastries were brushed with olive oil, then how many of the pastries submitted by Rashid and Mikhail, in terms of x, were brushed with butter?

a) 3X/20
b) 9X/40
c) 1X/4
d) 3X/8
e) 5X/12
Mathematics
1 answer:
givi [52]3 years ago
5 0

Answer:

3X/20 (option a) of the pastries submitted by Rashid and Mikhail were brushed with butter

Step-by-step explanation:

Rashid pastries (R)

Mikhail pastries (M)

Rashid and Mikhail submitted a total of x pastries

R+M=x (I)

Rashid made 2/3 as many pastries as Mikhail

(2/3)*R=M (II)

Using II in I

R+(2/3)*R=x

(5/3)*R = x

R=(3/5)*x (III)

Using III in I

(3/5)*x+M=x

M=x-(3/5)*x

M=(2/5)*x (IV)

Mikhail filo dough (MF)

Mikhail shortcrust dough (MS)

Rashid filo dough (RF)

Rashid shortcrust dough (RS)

Mikhail used filo dough for all of his pastries

MF=M

MS=0

Rashid used shortcrust dough for all of his pastries

RS=R

RF=0

Filo dough (FD)

FD=RF+MF=0+MF=MF=M (V)

5/8 of the filo dough pastries were brushed with olive oil

pastries brushed with olive oil (OI)

(5/8)*FD=OI

Using V

(5/8)*M=OI

Using IV

(5/8)*(2/5)*x=OI

(1/4)*x=OI (VI)

pastries brushed with butter (B)

Pastries made out of filo dough are brushed with either olive oil or butter (but not both)

FD=OI+B

B=FD-OI

Using V and VI

B= M - (1/4)*x

Using IV

B = (2/5)*x - (1/4)*x

B= (3/20)*x

3X/20 (option a) of the pastries submitted by Rashid and Mikhail were brushed with butter

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3 years ago
Read 2 more answers
If t and m are positive, t^2 + m^2 = 64 and (t+m)^2 = 98, what is tm?
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Answer:

17

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t^2 + m^2 = 64

(t+m)^2 = 98

(t+m)^2 = t^2 +2tm+ m^2

==>

t^2 +2tm+ m^2 = 98

t^2+m^2+2tm=98

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A 2-kg object is fired from a cannon at a 30º angle wrt to the horizontal. the initial speed is 35 m/s. how high will the object
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     <span> You have :
----------------

v0 = 35 m/s

B = angle of elevation = 30 deg

a suby = - g

v suby0 = ( v0 ) ( sin B )

v suby0 = ( 35 m/s ) ( sin 30 ) = 17.5 m/s

At maximum height :
------------------------------

v suby = vy* = 0.0

t = t*

y = ymax = y*

Basic kinematics gives :
-------------------------------------

a suby = dv suby / dt = -g ------> dt = dv suby /a suby

v suby = dy/dt ------> dt = dy / vsuby

dt = dv suby / a suby = dy / v suby

( v suby ) ( d v suby) = ( a suby ) dy = ( -g ) dy

Now integrate and get :
-----------------------------------

( v suby* )^2 - ( v suby0)^2 ( 1/2 ) = ( -g ) ( ymax )

ymax = [ ( v suby0 )^2 - ( v suby* )^2 ] / [ ( 2 ) ( g ) ]

ymax = ( 17.5 m/s )^2 - ( 0.0 m/s )^2 ] / [ ( 2 ) ( 9.807 m/s^2 ) ]

ymax = 15.6 m <------------------

Check the result:
--------------------------

t* = v suby0 / g = ( 17.5 m/s ) / ( 9.807 m/s^2 ) = 1.784 s

y* - y0 = ( v suby0 ) ( t* ) - ( g/2 ) ( t* )^2

y* = ( 17.5 m/s ) ( 1.784 s ) - ( 9.807 m/s^2 / 2 ) ( 1.784 s )^2

y* = ymax = 31.23 m - 15.61 m = 15.6 m

The ymax values agree.</span>
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3 years ago
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