1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mila [183]
3 years ago
13

How do you do 859/2 using long division

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0
So, you will put the numerator inside the symbol and the 2 outside of it so like

429.5
_____
2/859.0
-8
_
05
- 4
--
19
-18
----
10
-10
----
0

So, your answer would be 429.5
or 429 r 1
You might be interested in
Expand and simplify<br> (3y - 2)(y + 3)
Vedmedyk [2.9K]

Step-by-step explanation:

3y^2 + 7y - 6

5 0
3 years ago
Read 2 more answers
Y = 2/3 x -3 y = -3/2 x +2 what statement about the lines are true
Hoochie [10]

Answer:

The product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

Thus, the lines are perpendicular.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the lines

y = 2/3 x -3       --- Line 1

y = -3/2x +2      --- Line 2

<u>The slope of line 1</u>

y = 2/3 x -3       --- Line 1

By comparing with the slope-intercept form of the line equation

The slope of line 1 is: m₁ = 2/3

<u>The slope of line 2</u>

y = -3/2x +2      --- Line 2

By comparing with the slope-intercept y = mx+b form of the line equation

The slope of line 2 is: m₂ = -3/2

We know that when two lines are perpendicular, the product of their slopes is -1.

Let us check the product of two slopes m₁ and m₂

m₁ × m₂ = (2/3)(-3/2 )

m₁ × m₂ = -1

Thus, the product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

Thus, the lines are perpendicular.

7 0
2 years ago
Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the
KonstantinChe [14]

Answer:

The center of the circle is

(-\frac{3}{2},2)

Step-by-step explanation:

Let the equation of the circle be

x^2+y^2+2ax+2by+c=0, where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

0^2+0^2+2a(0)+2b(0)+c=0

\implies c=0

B(-3,0)

(-3)^2+0^2+2a(-3)+2b(0)+c=0

\implies 9+0-6a+0+c=0

\implies -6a+c=-9

But c=0

\implies -6a=-9

\implies a=\frac{3}{2}

C(1,2)

1^2+2^2+2a(1)+2b(2)+c=0

1+4+2a+4b+c=0

2a+4b+c=-5

Put the value of 'a' and 'c' to find 'b'

2(\frac{3}{2})+4b+0=-5

3+4b+0=-5

4b=-5-3

4b=-8

b=-2

Hence the center of the circle is

(-\frac{3}{2},2)

8 0
3 years ago
there are 2 1\2 bus loads of students standing in a parking lot. The students are getting ready to go on a field trip. 2\5 of th
Archy [21]
It would take only one full bus to carry only girls.
3 0
3 years ago
Read 2 more answers
(98 POINTS) (PLEASE HURRY!)
Montano1993 [528]

Answer:

1. no like terms

2. x^ 3 − x^ 2 − x + 1

3.x y + x + y + 1

4.x^ 3 + x^ 2 y + x y^ 2 + y^ 3

Lol

6 0
3 years ago
Other questions:
  • If the average life span of a dog is 12 years, how many hours can you expect a dog to live? 105,120 105,000 438,000 262,800 105,
    5·1 answer
  • Use the function f(x) to answer the questions: f(x) = 2x2 − x − 10
    6·1 answer
  • Solve : -0.375c - 11 = 13<br><br> please help me and thank youu :)
    11·2 answers
  • This is more a math question but no one is answering in the \"math\" section. . Compute 6.28x10^13 +6.30x10^11. Express your ans
    15·2 answers
  • Solve the linear equation 7x-3=67 for x
    14·2 answers
  • What is 762x44 explain your work
    11·1 answer
  • Can I please have some help?
    11·1 answer
  • Suppose that, in 2006, Canada produced 0.531 million computers. The total world production that year totaled 147 million compute
    7·1 answer
  • Please help, solve for x
    11·1 answer
  • Point-slope equation for perpendicular lines y=-2x-7 that passes through (-2,-3)
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!