Lets put the numbers in order...
6,7,7,8,8,9,9,10,11,30
Q1 = 7
Q2 = (8 + 9) / 2 = 17/2 = 8.5
Q3 = 10
IQR = Q3 - Q1 = 10 - 7 = 3 <== so the interquartile range is 3
mean absolute deviation...
the mean of our data is 10.5
now we subtract the mean from every data point....and find its absolute value
6 - 10.5 = -4.5.....| -4.5| = 4.5
7 - 10.5 = -3.5.....| -3.5| = 3.5
7 - 10.5 = -3.5.....|-3.5| = 3.5
8 - 10.5 = - 2.5....|-2.5| = 2.5
8 - 10.5 = -2.5....|-2.5| = 2.5
9 - 10.5 = -1.5....|-1.5| = 1.5
9 - 10.5 = -1.5....|-1.5| = 1.5
10 - 10.5 = -0.5..| -0.5| = 0.5
11 - 10.5 = 0.5...|0.5| = 0.5
30 - 10.5 = 19.5..|19.5| = 19.5
now we take the average of these numbers
(4.5+3.5+3.5+2.5+2.5+1.5 + 1.5 + 0.5+0.5+19.5) / 10 =
40/10 = 4 <== ur mean absolute deviation
In summary :
ur interquartie range (IQR) of ur data set is 3
ur mean absolute deviation (MAD) of ur data set is 4
Answer:
A. Candice should reject the null hypothesis as the 95% confidence interval does not contain 12 hours
Step-by-step explanation:
Given that:
Average watch hour = 12
sample size = 79
The 95% Confidence interval lies between 7.60 and 11.37.
Thus, since the average watch of students in her school does not lie within the interval between 7.60 and 11.37, Candice should reject the null hypothesis.
Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
first, make an equation:
then, add twelve to both sides to remove it from the right:
then just divide by (-3) to get the value of x:
The domain is all real numbers bc the domain is all x values and the lines continue going left and right and do not stop
