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ICE Princess25 [194]
4 years ago
5

The body of a man is lying in a pool of blood near the refrigerator in his kitchen. There is blood spatter on the refrigerator,

its corresponding wall, and an adjacent wall. The kitchen door shows evidence of a break-in with shattered glass and a broken door frame. Which type of sketch should the sketch artist use to best convey all the information? A) cross-projection sketch B) perspective sketch C) floor plan sketch D) elevation sketch
Chemistry
1 answer:
kolbaska11 [484]4 years ago
7 0
I think he or she should use option c
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How would I do this I’m so confused? Please helpppppp<br> (The work is wrong btw)
alexandr402 [8]

I don't know much about this, but probably the reason why your teacher circled 300k is because of what's in the photo below. If you couldn't tell from the photo, its because 300k isn't negative. Anyway this is my guess, based on my limited knowledge.

8 0
3 years ago
Indica el período, el grupo, el nombre y el número atómico de los elementos que se representan con las siguientes configuracione
motikmotik

Answer:

have g8igcicg9ccgco

Explanation:

gcohogxzrxog floor. gi gi gi gi. r. uvgi7rz. g yde6ifkg. gg g goog oh g of ifz8fd8dti

4 0
3 years ago
A solution is
Burka [1]

Answer:

the first one. a homogeneous mixture.

Explanation:

hope this helps :)

7 0
3 years ago
A chemist titrates 110.0 mL of a 0.7684 M methylamine (CH3NH2) sotion with 0.4469 M HNO3 solution at 25 °C. Calculate the pH at
Firdavs [7]

Answer: The pH at equivalence point for the given solution is 5.59.

Explanation:

At the equivalence point,

            n_{HNO_{3}} = n_{CH_{3}NH_{2}}

So, first we will calculate the moles of CH_{3}NH_{2} as follows.

      n_{CH_{3}NH_{2}} = 0.764 M \times \frac{110 ml}{1000 ml/L}      

                     = 0.0845 mol

Now, volume of HNO_{3} present will be calculated as follows.

          Volume = \frac{\text{no. of moles}}{\text{Molarity}}

                        = \frac{0.0845}{0.4469 M}

                        = 0.1891 L

Therefore, the total volume will be the sum of the given volumes as follows.

                    110 ml + 189.1 ml

                  = 299.13 ml

or,               = 0.2991 L

Now, [CH_{3}NH_{3}^{+}] = \frac{0.0845 mol}{0.2991 L}

                        = 0.283 M

Chemical equation for this reaction is as follows.

     CH_{3}NH_{3}^{+} + H_{2}O \rightleftharpoons CH_{3}NH_{2} + H_{3}O^{+}

As,      k_{a} = \frac{k_{w}}{k_{b}}        

                     = \frac{10^{-14}}{10^{-3.36}}

                     = 2.29 \times 10^{-11}

Now,   [HNO_{3}] = \sqrt{k_{a}[CH_{3}NH_{3}^{+}]}

                      = \sqrt{2.29 \times 10^{-11} \times 0.283}

                      = 2.546 \times 10^{-6}

Now, pH will be calculated as follows.

              pH = -log [H_{3}O^{+}]

                    = -log (2.546 \times 10^{-6})

                    = 5.59

Thus, we can conclude that pH at equivalence point for the given solution is 5.59.

6 0
3 years ago
el acido fosforico, glucosa , fructosa ,pentacloruro de fosforo se identifica como compuesto o organicos
bija089 [108]

Answer:

La reacción con pentacloruro de fósforo (PCl5) es una característica de los compuestos orgánicos que contienen un grupo hidroxilo y esta reacción se utiliza para identificar estos compuestos en un análisis orgánico.

4 0
3 years ago
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