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kolezko [41]
4 years ago
9

What are the requirements for two atoms to be isotopes of each other?

Chemistry
2 answers:
mart [117]4 years ago
5 0
By definition, isotopes belong to the same element with a specific atomic number. The two atoms would have the same number of protons, but differ in the number of neutrons. It can also be stated that the two atoms would have the same atomic number but different mass numbers. These are the requirements for two atoms to be called isotopes. 
WINSTONCH [101]4 years ago
3 0

Explanation:

An isotope is defined as the specie which contains same number of protons but different number of neutrons.  

For example, ^{12}_{6}C and ^{13}_{6}C are isotopes.

Number placed at the bottom of an element's symbol represents atomic number whereas number placed at the top of an element's symbol represents atomic mass (sum of total number of protons and neutrons).

Therefore, we can conclude that requirement for two atoms to be isotopes of each other is that they should contain same number of protons.

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Weak bonds require less energy to form than strong bonds

Explanation:

According to Coulomb's law, the force between two species is inversely proportional to the distance between them. That said, the bigger the atoms are, the greater the bond length should be to form a molecule.

As a result, for a greater bond length, the attraction force is lower than for a shorter bond length. This implies that large atoms would form weak bonds and small atoms would form strong bonds.

Bond energy is defined as the amount of energy required to break the bond. If a bond is weak, it would require a low amount of energy to break it. This is also true for energy of formation, as it's the same process taking place in the opposite direction.

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How many milliliters are in one milligram?
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4 years ago
An aluminum cup of 140 cm3 capacity is completely filled with glycerin at 20°C. How much glycerin will spill out of the cup if t
mel-nik [20]

Explanation:

The given data is as follows.

    coefficient of volume expansion of glycerin (\beta) = 5.1 \times 10^{-4} 1/^{o}C

     linear expansion coefficient of aluminum, (\alpha_{A}) = 23 \times 10^{-6} 1/^{o}C  

              Volume = 100 cm^{3}

The increase in volume of the cup will be calculated as follows.

                    \Delta V_{c} = V \times 3 \times \alpha \times \Delta T

                                 = 100 cm^{3} \times 3 \times 23 \times 10^{-6} \times (31 - 20)^{o}C

                                 = 75900 \times 10^{-6} cm^{3}

                                 = 0.0759 cm^{3}

Formula for increase in volume  of glycerine is as follows.

               \Delta V_{g} = V \times \beta_{g} \times \Delta T

                              = 100 cm^{3} \times 5.1 \times 10^{-4} 1/^{o}C \times (31 - 20)^{o}C

                              = 0.5610 cm^{3}

Therefore, volume of glycerin spilled is calculated as follows.

                        \Delta V = \Delta V_{g} - \Delta V_{c}

                                     = (0.5610 - 0.0759) cm^{3}

                                     = 0.4851 cm^{3}

Thus, we can conclude that 0.4851 cm^{3} glycerin will spill out of the cup.

6 0
3 years ago
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