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user100 [1]
3 years ago
7

Last giveaway! 30 <3

Chemistry
2 answers:
Scorpion4ik [409]3 years ago
8 0

Answer:

Hi

Explanation:

Hi hi

NISA [10]3 years ago
5 0

Answer:

Ty!~

Explanation:

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MAVERICK [17]

Answer:

           

Explanation:

       

7 0
3 years ago
The conversion of methyl isonitrile to acetonitrile in the gas phase at 250 °C CH3CN(g) is first order in CH3NC with a rate cons
nadya68 [22]

Answer: The concentration of CH_3NC will be 1.56\times 10^{-2}M after 416 seconds have passed.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant = 3.00\times 10^{-3}s^{-1}

t = age of sample = ?

a = let initial amount of the reactant = 5.45\times 10^{-2}M

a - x = amount left after decay process = 1.56\times 10^{-2}M

t=\frac{2.303}{3.00\times 10^{-3}}\log\frac{5.45\times 10^{-2}}{1.56\times 10^{-2}}

t=416s

The concentration of CH_3NC will be 1.56\times 10^{-2}M after 416 seconds have passed.

5 0
3 years ago
_________ is caused by deficiency of Vitamin A​
ivann1987 [24]

Answer:

eye weakness is caused by deficiency of vitamin A

4 0
3 years ago
Read 2 more answers
Which formulas could represent the empirical formula and the molecular formula of a given compound?
Alina [70]

Answer:

d

Explanation:

d

7 0
3 years ago
Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +
qwelly [4]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

X(s)+\frac{1}{2}O_2(g)+CO_2(g)\rightarrow XCO_3(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) X(s)+\frac{1}{2}O_2(g)\rightarrow XO(s)    \Delta H_1=-668.5kJ

(2) XCO_3(s)\rightarrow XO(s)+CO_2     \Delta H_2=+384.3kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times \Delta H_1]+[1\times (-\Delta H_2)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-668.5))+(1\times (-384.3))=-1052.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

7 0
3 years ago
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