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Talja [164]
3 years ago
6

How far in advance is weather forecasting most accurate

Chemistry
2 answers:
Vesnalui [34]3 years ago
8 0

I'm like 99% sure its one week

Orlov [11]3 years ago
8 0

yup answer is one week just finished the test

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(2k-1)²<br> what the answer pls.​
Sedaia [141]

Answer:

4k^2-4k+1

Explanation:

Plx give brainlyest

7 0
2 years ago
Will a double replacement reaction occur if a potassium hydroxide solution is mixed with a lead(II) nitrate solution? Briefly ex
ohaa [14]
No - a precipitation will occur though. Potassium nitrate is soluble in water, so the potassium and nitrate ions will remain spectator ions and stay in solution. Lead (II) hydroxide is not soluble, and will precipitate out of solution to form a solid product.
3 0
3 years ago
Read 2 more answers
What is the volume, in liters, of 576 grams of so2 gas at stp?
katen-ka-za [31]
The volume  in  liters  of  576 grams  of SO2  gas  at STP  is   calculated as below

calculate the moles of SO2 = mass/molar  mass

= 576 g/64 g /mol  = 9 moles

At  STP  1mole =22.4 L
what  9 mole =? liters

by cross  multiplication

= 22.4 L x  9 moles/ 1moles = 201.6 liters
5 0
2 years ago
A hydrocarbon, containing only C and H, can react with excess oxygen gas to produce carbon dioxide and water. The result of the
Tcecarenko [31]
I believe the answer you are looking for would be HC

5 0
3 years ago
Read 2 more answers
How many grams of NaHCO3 are needed to prepare 250 mL of 0.50 M<br> NaHCO3?
forsale [732]

Answer:

10.5g

Explanation:

First, let us calculate the number of mole of NaHCO3 present in the solution. This is illustrated below:

Volume = 250mL = 250/1000 = 0.25L

Molarity = 0.5M

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.5 x 0.25

Mole = 0.125 mole

Now, we shall be converting 0.125 mole of NaHCO3 to grams to obtain the desired result. This can be achieved by doing the following:

Molar Mass of NaHCO3 = 23 + 1 + 12 +(16x3) = 23 + 1 +12 +48 = 84g/mol

Number of mole of NaHCO3 = 0.125 mole

Mass of NaHCO3 =?

Mass = number of mole x molar Mass

Mass of NaHCO3 = 0.125 x 84

Mass of NaHCO3 = 10.5g

Therefore, 10.5g of NaHCO3 is needed.

6 0
2 years ago
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