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Talja [164]
3 years ago
6

How far in advance is weather forecasting most accurate

Chemistry
2 answers:
Vesnalui [34]3 years ago
8 0

I'm like 99% sure its one week

Orlov [11]3 years ago
8 0

yup answer is one week just finished the test

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<em><u>30.11x1</u></em><em><u>0</u></em><em><u>²</u></em><em><u>³</u></em>

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What the symbol for the oxygen isotope with 10 neutrons?
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when nahco3 completely decomposes, it can follow this balanced chemical equation: 2nahco3 → na2co3 h2co3 determine the theoretic
AnnZ [28]

Using stoichiometry, 3.24 grams NaHCO_{3} will yield 2.04 grams Na_{2} CO_{3} and 1.20 grams H_{2} CO_{3}. But in an actual decomposition where the mass of one of the products was measured to be 2.01 grams, which is Na_{2} CO_{3}, the percent yield is 98.34%.

Stoichiometry is defined as the relationship between  the amounts of substances that are involved in chemical reactions.

Mole ratio relates the amounts in moles of any two substances by looking at the coefficients in front of each species in the balanced chemical equation.

For the decomposition of NaHCO_{3}, it follows the balanced chemical equation:

2NaHCO_{3} = Na_{2} CO_{3}+H_{2} CO_{3}

2 moles of NaHCO_{3} will decompose into 1 mole of Na_{2} CO_{3} and 1 mole of H_{2} CO_{3}

mole ratio = 2 : 1 : 1

If the mass of NaHCO_{3} sample is 3.24 grams, then

molar mass = m/n

84.007 g/mol = 3.24 g/n

n = 0.03856821455 mol NaHCO_{3}

and using the mole ratio 2 : 1 : 1, theoretically,

0.03856821455 mol NaHCO_{3} will yield 0.01928410728 mol Na_{2} CO_{3} and 0.01928410728 mol H_{2} CO_{3}.

If there's 0.01928410728 mol Na_{2} CO_{3}, its mass is:

molar mass = m/n

105.9888 g/mol = m/ 0.01928410728

m = 2.043899389 g Na_{2} CO_{3}

On the other hand, if there's 0.01928410728 mol H_{2} CO_{3}, then

molar mass = m/n

62.03 g/mol = m/0.01928410728

m = 1.196193174 g H_{2} CO_{3}

If the mass of one of the products was measured to be 2.01 grams, then it must be     Na_{2} CO_{3} since the experimental value is much closer to the theoretical mass.

Calculating its percent yield,

percent yield = actual yield/theoretical yield x 100%

percent yield = 2.01 g/2.043899389 g x 100%

percent yield = 98.34143552% = 98.34%

To learn more about stoichiometry: brainly.com/question/25829169

#SPJ4

6 0
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