Using stoichiometry, 3.24 grams will yield 2.04 grams and 1.20 grams . But in an actual decomposition where the mass of one of the products was measured to be 2.01 grams, which is , the percent yield is 98.34%.
Stoichiometry is defined as the relationship between the amounts of substances that are involved in chemical reactions.
Mole ratio relates the amounts in moles of any two substances by looking at the coefficients in front of each species in the balanced chemical equation.
For the decomposition of , it follows the balanced chemical equation:
2 moles of will decompose into 1 mole of and 1 mole of
mole ratio = 2 : 1 : 1
If the mass of sample is 3.24 grams, then
molar mass = m/n
84.007 g/mol = 3.24 g/n
n = 0.03856821455 mol
and using the mole ratio 2 : 1 : 1, theoretically,
0.03856821455 mol will yield 0.01928410728 mol and 0.01928410728 mol .
If there's 0.01928410728 mol , its mass is:
molar mass = m/n
105.9888 g/mol = m/ 0.01928410728
m = 2.043899389 g
On the other hand, if there's 0.01928410728 mol , then
molar mass = m/n
62.03 g/mol = m/0.01928410728
m = 1.196193174 g
If the mass of one of the products was measured to be 2.01 grams, then it must be since the experimental value is much closer to the theoretical mass.
Calculating its percent yield,
percent yield = actual yield/theoretical yield x 100%
percent yield = 2.01 g/2.043899389 g x 100%
percent yield = 98.34143552% = 98.34%
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