Mole ratio:
<span> MgCl</span>₂<span> + 2 KOH = Mg(OH)</span>₂<span> + 2 KCl
</span>
1 mole MgCl₂ -------------- 1 mole Mg(OH)₂
Answer B
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Answer:
B
Explanation:
as it depends on electronic configuration
D. reproductive cells uwu
Pb(NO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) + 2 NaNO3 (aq)
Starting with with 200.0 grams of Pb(NO3)2 and 120.0 grams of NaI:
A. What is the limiting reagent?
B. How many grams of PbI2 is theoretically formed?
C. How many grams of the excess reactant remains?
D. If 48 grams of NaNO3 actually formed in the reaction, what is the percent yield of this reaction?
Answer:
Strong acid breaks up into ions
Explanation: