Identical balls are dropped from the same initial height and bounce back to half the initial height. In Case 1 the ball bounces
1 answer:
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Answer:
4.8 ton
Explanation:
We are given that
Mass,m=77 ton
Displacement,s=3500 ft
We have to find the force parallel to the incline would be required to hold the monolith on this causeway.
The force parallel to the incline would be required to hold the monolith on this causeway=
Using the formula
The force parallel to the incline would be required to hold the monolith on this causeway=
Answer:
58.5 m
Explanation:
First of all, we need to find the total time the ball takes to reach the water. This can be done by looking at the vertical motion only.
The initial vertical velocity of the ball is
where
u = 21.5 m/s is the initial speed
is the angle
Substituting,
The vertical position of the ball at time t is given by
where
h = 13.5 m is the initial heigth
is the acceleration of gravity (negative sign because it points downward)
The ball reaches the water when y = 0, so
Which gives two solutions: t = 3.27 s and t = -0.84 s. We discard the negative solution since it is meaningless.
The horizontal velocity of the ball is
And since the motion along the horizontal direction is a uniform motion, we can find the horizontal distance travelled by the ball as follows: